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svp [43]
3 years ago
9

Simplify sqrt(x^2-16)

Mathematics
1 answer:
Softa [21]3 years ago
4 0
Remember for this type of question.I'm guessing you make the equation equal to 0. Then square both sides the (X ^2-16) and 0. Then the square root goes away. Then you factor it according to the difference of squares method. By taking the square root of x^2 and 16. So ultimately it turns into 2 binomials according to the difference of squares method. The simplified answer would be (X-4)(X+4)=0. To solve for x in each case, take each respective equation separately and make it equal to 0. Solve for x.
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tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

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Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

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