The exponential form when [x²y³)^(¹/₃)]/[∛x²y] is simplified gives us; [x^(²/₃) * y]/[x^(²/₃) * y^(¹/₃)]
<h3>How to simplify exponents?</h3>
The power of a digit defines a base number raised to the exponent, where base number is the factor which is multiplied by itself while exponent denotes the number of times the same base number is multiplied.
We want to simplify the exponents; [x²y³)^(¹/₃)]/[∛x²y]
Using rule of exponents, we have;
[x^(²/₃) * y]/[x^(²/₃) * y^(¹/₃)]
Read more about Exponents at; brainly.com/question/12882204
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Answer:
Step-by-step explanation:
<u>Quadratic Function</u>
The quadratic function can be expressed in the following form:
Where a is a real number different from 0, and x1, x2 are the roots or zeroes of the function.
From the conditions stated in the problem, we know
x_1=1+\sqrt{2}, \ x_1=1-\sqrt{2}
Substitute in the general formula above:
Operate the indicated product
To find the value of a, we use the y-intercept which is the value of y when x=0, thus
It follows that
Thus, the required quadratic function is
Or, equivalently
Answer:
9+9
Step-by-step explanation:
9+9=18
23-5=18
I got 0.4, not sure if that’s correct, but i solved it as if there was only one variable. since it’s 5*y i did the opposite and divided and got 6x+y=2.4. then i did 6/6 and did 2.4/6 and got x+y=0.4. i’d wait till more people answer to be sure that is correct