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3 years ago

The vertex of this parabola is at (-3, -2). which of the following could be its equation?

Mathematics

2 answers:

professor190 [17]3 years ago

7 0

Answer:

Since the vertex is (-3,-2) The x value should be +3

Karolina [17]3 years ago

4 0

Answer:

The answer would be "B", I just took the test.

Step-by-step explanation:

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Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same ti

Mariulka [41]

Let time be x distance be y

140x=y-(1)
290x=360-y-(2)

Put value in eq(2)

$\\ \rm\longmapsto 290x=360-(140y)$

$\\ \rm\longmapsto 440x=360$

$\\ \rm\longmapsto x=1.2min$

Put it in eq(1)

d=1.2(140)=168m

7 0

2 years ago

Write the degree of the following polynomials.<br>a⁴+a³b²+a²b²+b⁵

Whitepunk [10]

Answer:

downloadable content of the year and I have a nice day ahead of

3 0

3 years ago

Read 2 more answers

9 11/12- 2 8/11 is a problem that i need help on

Vitek1552 [10]

Hey there!!

Okay here are the steps you can follow!

9 11/12 ----> improper fraction ----> 119/12
2 8/11 ----> improper fraction ----> 30/11

119/12 - 30/11
(119/12 - 30/11) * 132
11(119) - 12(30)
1309 - 360
<u>949</u>

3 0

3 years ago

9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

SSSSS [86.1K]

Answer:

Part 4) $r=84\ units$

Part 9) $sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) $sin(\theta)=-\frac{9\sqrt{202}}{202}$

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

$C=2\pi r$

using proportion

$\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}$

simplify

$\frac{r}{180^o}=\frac{56}{120^o}$

solve for r

$r=\frac{56}{120^o}(180^o)$

$r=84\ units$

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

$cos^2(\theta)+sin^2(\theta)=1$

we have

$cos(\theta)=-\frac{2}{3}$

substitute the given value

$(-\frac{2}{3})^2+sin^2(\theta)=1$

$\frac{4}{9}+sin^2(\theta)=1$

$sin^2(\theta)=1-\frac{4}{9}$

$sin^2(\theta)=\frac{5}{9}$

square root both sides

$sin(\theta)=\pm\frac{\sqrt{5}}{3}$

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

$sin(\theta)=-\frac{\sqrt{5}}{3}$

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?

see the attached figure to better understand the problem

In the right triangle ABC of the figure

$sin(\theta)=\frac{BC}{AC}$

Find the length side AC applying the Pythagorean Theorem

$AC^2=AB^2+BC^2$

substitute the given values

$AC^2=11^2+9^2$

$AC^2=202$

$AC=\sqrt{202}\ units$

$sin(\theta)=\frac{9}{\sqrt{202}}$

simplify

$sin(\theta)=\frac{9\sqrt{202}}{202}$

Remember that

The point (11,-9) lies in Quadrant IV

then

The value of sin(∅) is negative

therefore

$sin(\theta)=-\frac{9\sqrt{202}}{202}$

5 0

3 years ago

B and D are points of tangency. Find the value of x using the diagram.

svp [43]

Answer:

answer is here check it

Step-by-step explanation:

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ly/3a8Nt8n

4 0

2 years ago