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BartSMP [9]
3 years ago
7

The vertex of this parabola is at (-3, -2). which of the following could be its equation?

Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer:

B

Since the vertex is (-3,-2) The x value should be +3

Karolina [17]3 years ago
4 0

Answer:

The answer would be "B", I just took the test.

Step-by-step explanation:

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Two groups of tourists are on the same floor of a skyscraper they are visiting, and they board adjacent elevators at the same ti
Mariulka [41]

Let time be x distance be y

  • 140x=y-(1)
  • 290x=360-y-(2)

Put value in eq(2)

\\ \rm\longmapsto 290x=360-(140y)

\\ \rm\longmapsto 440x=360

\\ \rm\longmapsto x=1.2min

Put it in eq(1)

  • d=1.2(140)=168m
7 0
2 years ago
Write the degree of the following polynomials.<br>a⁴+a³b²+a²b²+b⁵​
Whitepunk [10]

Answer:

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3 0
3 years ago
Read 2 more answers
9 11/12- 2 8/11 is a problem that i need help on
Vitek1552 [10]
Hey there!!

Okay here are the steps you can follow!

9 11/12  ---->  improper fraction  ----> 119/12
2 8/11  ---->  improper fraction  ---->  30/11

119/12  -  30/11
(119/12  -  30/11) * 132
11(119)  -  12(30)
1309 - 360
<u>949</u>
3 0
3 years ago
9. A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?
SSSSS [86.1K]

Answer:

Part 4) r=84\ units

Part 9) sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) sin(\theta)=-\frac{9\sqrt{202}}{202}

Step-by-step explanation:

Part 4) A circle has an arc of length 56pi that is intercepted by a central angle of 120 degrees. What is the radius of the circle?

we know that

The circumference of a circle subtends a central angle of 360 degrees

The circumference is equal to

C=2\pi r

using proportion

\frac{2\pi r}{360^o}=\frac{56\pi}{120^o}

simplify

\frac{r}{180^o}=\frac{56}{120^o}

solve for r

r=\frac{56}{120^o}(180^o)

r=84\ units

Part 9) Given cos(∅)=-2/3 and ∅ lies in Quadrant III. Find the exact value of sin(∅) in simplified form

Remember the trigonometric identity

cos^2(\theta)+sin^2(\theta)=1

we have

cos(\theta)=-\frac{2}{3}

substitute the given value

(-\frac{2}{3})^2+sin^2(\theta)=1

\frac{4}{9}+sin^2(\theta)=1

sin^2(\theta)=1-\frac{4}{9}

sin^2(\theta)=\frac{5}{9}

square root both sides

sin(\theta)=\pm\frac{\sqrt{5}}{3}

we know that

If ∅ lies in Quadrant III

then

The value of sin(∅) is negative

sin(\theta)=-\frac{\sqrt{5}}{3}

Part 10) The terminal side of ∅ passes through the point (11,-9). What is the exact value of sin(∅) in simplified form?    

see the attached figure to better understand the problem

In the right triangle ABC of the figure

sin(\theta)=\frac{BC}{AC}

Find the length side AC applying the Pythagorean Theorem

AC^2=AB^2+BC^2

substitute the given values

AC^2=11^2+9^2

AC^2=202

AC=\sqrt{202}\ units

so

sin(\theta)=\frac{9}{\sqrt{202}}

simplify

sin(\theta)=\frac{9\sqrt{202}}{202}

Remember that      

The point (11,-9) lies in Quadrant IV

then      

The value of sin(∅) is negative

therefore

sin(\theta)=-\frac{9\sqrt{202}}{202}

5 0
3 years ago
B and D are points of tangency. Find the value of x using the diagram.
svp [43]

Answer:

answer is here check it

Step-by-step explanation:

bit.^{}

ly/3a8Nt8n

4 0
2 years ago
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