Evaluate: 3y + 1 = 13 + 4y **What do you move first?!**
1 answer:
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The x-intercept of f(x) = (x + 6)(x - 3)
f(x) = 0 → (x + 6)(x - 3) = 0 → x + 6 =0 or x - 3 =0
x = -6 or x = 3
Therefore the x-intercepts are: (-6; 0) and (3; 0)
Your answer is (-6; 0)
f(x) = 0 → (x + 6)(x - 3) = 0 → x + 6 =0 or x - 3 =0
x = -6 or x = 3
Therefore the x-intercepts are: (-6; 0) and (3; 0)
Your answer is (-6; 0)