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klasskru [66]
4 years ago
3

Suppose Host A wants to send a large file to host B. The path from Host A to Host B has three links, of rates R1 = 500 kbps, R2=

2 Mbps, and R3 = 1 Mbps. Assuming no other traffic in the network, what is the throughput for the file transfer? 500 kbps
Computers and Technology
1 answer:
shusha [124]4 years ago
5 0

Answer:

500kbps

Explanation:

Bandwidth is the actual amount of data that a network is capable of transferring theoretically.

Throughput is the actual amount of data passing through a connection. It is the rate (usually measured in bps- bits per sec or pps - packets per second) at which packets or bits are successfully delivered over a network channel

If R₁=500 kbps, R₂=2 Mbps, and R₃ = 1 Mbps.

Since there is no other traffic in the link from Host A to Host B, the Throughput is the minimum of the links between Host A and Host B. Therefore:

Throughput= Mininum(R₁,R₂,R₃)

=500kbps

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