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2 years ago

Carl wants to add two new characters to the extraterrestrial battleship game he's

Computers and Technology

1 answer:

nikitadnepr [17]2 years ago

6 0

The option that best explains the game is that a game can have multiple instances using the same class.

<h3>Can a class have multiple instances?</h3>

A game is one that can always create multiple instances of a class. This is known to be the reason that classes are made.

Conclusively, each object often has its own specific inner variables and they do not have only if they are static but games of multiple instances is the reason why there is only one class with the new characters.

Learn more about Games from

brainly.com/question/1786465

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Which operating system became obsolete with the arrival of a more advanced graphical user interfaces

12345 [234]

The answer is Ms Dos

6 0

3 years ago

I NEED HELP!!! BRAINLIEST!!!

Trava [24]

Answer:

DHCP Dynamic Host Configuration Protocol:

Is a network service that automatically assigns IP addresses and other TCP/IP configuration information on network nodes configured as DHCP clients. Server allocates IP addresses to DHCP clients dynamically. Should be configured with at least one DHCP scope. Scope contains a range of IP addresses and a subnet mask, and can contain other options, such as a default gateway and Domain Name System. Scope also needs to specify the duration of the lease and usage of an IP affects after which the node needs to renew the lease with the SHCP server. Determines the duration, which can be set for a defined time period or for an unlimited length of time.

DNS Domain Name Service: Is a TCP/IP name resolution service that translates FQDNs into IP addresses. System of hierarchical databases that are stored on separate DNS servers on all networks that connect to the Internet. DNS servers store, maintains and update databases, they respond to DNS client name resolution requests to translate host names into IP addresses.

DNS Components

DNS database is divided logically into a heieratchical grouping of domains. Physically into files called zones. Zone files contain the actual IP-to-host name mapping for one or more domains. Zone files is stored on the DNS server that is responsible for resolving hot names for the domains contained in the zone. Each network node in that domain will have a host record within the domain's zone files. Includes the node's host name, FQDN, and assigned IP address.

DNS Servers

*If you are configuring static IP addresses, including the IP address of the default DNS servers as you configure each client.

*If you are using DHCP, use the DHCP scope options to specify the IP Explanation:

3 0

3 years ago

Read 2 more answers

What happens if you create multiple accounts just to get points faster?

balandron [24]

I don’t think it will work sadly. You can probably accumulate points though on your pre existing account. Hope that helps!

8 0

3 years ago

c++ Write a program that reads a list of words. Then, the program outputs those words and their frequencies. The input begins wi

Margaret [11]

Answer:

The following are the program in the C++ Programming Language:

#include <iostream> //header file

#include <string> //header file

#include <vector> //header file

//name space

using namespace std;

//main function

int main() {

vector<string> word; //set variable

vector<int> c; //set variable

int s, counts = 0; //set variable

string strng; //set variable

cout<<"Enter the size of string: "; //print message

cin >> s; //get input

cout<<"Enter the string: "; //print message

for(int i = 0; i < s; ++i) { //set for loop

cin >> strng; //get input

word.push_back(strng);

}

for(int i = 0; i < s; ++i) { //set for loop

counts = 0;

for(int j = 0;j<word.size();j++){ //set for loop

if(word[j] == word[i]){ //set if statement

counts++; //increament in counts

}

c.push_back(counts);

}

for(int i = 0; i < s; ++i) {

cout << word[i] << " " << c[i] << endl;//print result

}

return 0;

}

<u>Output</u>:

Enter the size of string: 2

Enter the string: hello sir

hello 1

sir 1

Explanation:

Here, we define three header files <iostream>, <String>, <vector> and namespace "std" after that we define main() method inside it.

Then, we set two vector type variables first one is string variable "word" and the second one is integer variable "c".
Then we set two integer variable "s" and "counts" and variable "counts" assign to 0.
Then, we get input from the user in variable "s" for the length of the loop.
Then, we set for the loop inside it, we get input in the variable "strng" from the user.
Then, we set the for loop for count the string repetition if any word comes again in the string then the value of count will increase.
Finally, we set for a loop to print the result.

4 0

3 years ago

2. Using the Book class developed in HW 4, write an application, BookLibrary, that creates a library (array) of up to 10 books a

qwelly [4]

BookLibrary, that creates a library (array) of up to 10 books. If the user selects the add option, issue an error message if the library is full.If the book with that title exists, issue an error message

Explanation:

import java.util.Scanner;

import java.util.Arrays;

public class Derro_BooksLibrary {

public static void main(String[] args) {

Derro_Books[] Library = new Derro_Books[10];

Scanner scan = new Scanner(System.in);

Derro_Books book1 = new Derro_Books("", 20);

Derro_Books book2 = new Derro_Books("hi", 10);

Library[0] = book1;

Library[1] = book2;

System.out.println("Enter 1 for add, 2 for delete, 3 for change, 4 to stop application: ");

int answer = scan.nextInt();

int counter = 0;

int z = 0;

while (true) {

if (answer == 1) {

for (Derro_Books book : Library) {

counter = counter + 1;

}

if (counter == 10) {

System.out.println("Library full");

}

System.out.println("Enter Title: ");

String title = scan.nextLine();

for (int i = 0; i < Library.length; i++) {

if (title == Library[i].getTitle()) {

System.out.println("No Duplicated Books Titles Are Allowed");

break;

}

else {

z++;

}

if (z < Library.length) {

System.out.println("Enter number of pages: ");

int pages = scan.nextInt();

Library[z + 1] = new Derro_Books(title, pages);

}

if (answer == 2){

if (Library.length == 0) {

System.out.println("Library is empty");

}

System.out.println("Enter title of book: ");

String title2 = scan.nextLine();

for (int d = 0; d < Library.length; d++) {

if (title2 == Library[d].getTitle())

// Delete book

System.out.println("Deleted book: " + title2);

else

System.out.println("Book does not exist");

}

if (answer == 3) {

if (Library.length == 0) {

System.out.println("Library is empty.");

} else {

System.out.println("Enter book title: ");

String title3 = scan.nextLine();

for (int y = 0; y < Library.length; y++) {

if (title3 != Library[y].getTitle())

continue;

else {

System.out.println("Enter number of pages: ");

int pages = scan.nextInt();

Library[y] = new Derro_Books(title3, pages);

}

String[] StringList = new String[10];

for (int y = 0; y < Library.length; y++) {

StringList[y] = Library[y].getTitle();

}

Arrays.sort(StringList);

for (String bookt : StringList) {

System.out.println(bookt + Library);

}

6 0

3 years ago