Answer:
The height of the tank is 0.5 yards.
Step-by-step explanation:
To determine what is the height, in yards, of a cylindrical water tank that holds 1,884 cubic yards of water and has a diameter of 120 feet, knowing that the volume of a cylinder is equal to pi multiplied by the radius squared, multiplied by the height, the following calculation must be done:
1 foot = 0.3333 yards
R = Diameter / 2
R = 120/2 = 60
3.14 x 60 ^ 2 x H = 1,884
3.14 x 3,600 x H = 1,884
3.14 x 1,200 x H = 1,884
3.768 x H = 1.884
H = 1,884 / 3,768
H = 0.5
Therefore, the height of the tank is 0.5 yards.
The reflected points are (4, -1) and (-2, 6).
This is pretty simple. All you have to do is make the first and second fraction share a denominator by multiplying them by each other.
6 <span>• 9 = 54
Then multiply each numerator by the opposing denominator.
1 </span><span>• 9 = 9
2 </span><span>• 6 = 12
Here are the new fractions:
9/54
12/54
Now add the 9 and 12 together.
9 + 12 = 21
The complete fraction:
21/54
Subtract 21 from 54 so you can get the remainder of the sweater.
54 - 21 = 33
This is the remainder fraction:
33/54
Can you simplify this? Yes, of course! They can both be divided by 3!
11/18
That is the remainder of the sweater. But you still have to divide it in half! After all, Linda only knitted half of the remaining sweater. Dividing it in half can be done just by multiplying the denominator by 2.
11/36
That should be your answer! Apologies if I got something wrong.</span>
Answer:
1. A = 2x; P = 4x+2. A = 4; P = 10.
2. A = y² +2; P = 4y +2. A = 27; P = 22.
Step-by-step explanation:
1. The area is the sum of the marked areas of each of the tiles:
A = x + x
A = 2x
__
The perimeter is the sum of the outside edge dimensions of the tiles. Working clockwise from the upper left corner, the sum of exposed edge lengths is ...
P = 1 + (x-1) + x + 1 + (x+1) + x
P = 4x +2
__
When x=2, these values become ...
A = 2·2 = 4 . . . . square units
P = 4·2+2 = 10 . . . . units
_____
2. Again, the area is the sum of the marked areas:
A = y² + 1 + 1
A = y² +2
__
The edge dimension of the square y² tile is presumed to be y, so the perimeter (starting from upper left) is ...
P = y +(y-2) +1 +2 +(y+1) +y
P = 4y +2
__
When y=5, these values become ...
A = 5² +2 = 27 . . . . square units
P = 4·5 +2 = 22 . . . . units
There are 30 players in the tournament
