Answer #2 becuase i dont knoe the answer worth 10 points

Twelve pens and 16 pencils will be placed in bags with equal number of each item.

Alla [95]

You divide 16 into 12 and get 1.3 repeating

5 0

2 years ago

Read 2 more answers

A theatre has 50 seats on the front row. There are 4 additional seats in each following row.

alexandr402 [8]

$\boxed { \boxed { T_n = a_1 + d(n - 1)}}$

$\text {Given that }a_1 = 50 \text { and } d = 4$

$T_n = 50 + 4(n - 1)$

$T_n = 50 + 4n - 4$

$T_n = 46 + 4n$

$\boxed { \boxed {T_n = 46 + 4n }}$

When n = 20,
$T_{20} = 46 + 4(20) = 126$

$\boxed { \boxed {\text{Answer: The 20th term is 126}}}$

4 0

3 years ago

PLEASE HELP! I HAVE TWO QUESTIONS AND WILL GIVE 100PTS AND BRAINLIEST IF CORRECT!

Volgvan

Answer:

1) $283.50

2) 65.21 meters.

Step-by-step explanation:

Part 1)

We know that a spool of ribbon holds 6.75 meters.

A craft club buys 21 spools.

So, the total length of ribbon bought is:

$T=21(6.75)=141.75\text{ meters}$

Each meter costs $2. So, the total cost will be:

$141.75(2)=\$ 283.50$

Part 2)

A spool holds 6.75 meters.

We bought 21 of them, so that total length we have is 141.75 meters.

The club used 76.54 meters.

So, the amount of ribbon that is left is represented by:

$141.75-76.54$

Subtract:

$=65.21\text{ meters}$

So, 65.21 meters of ribbon will be left.

7 0

2 years ago

Read 2 more answers

Please help!? 5 Stars! :0 :(

zvonat [6]

OK. These problems are easy if you know the quadratic formula,
and they're impossible if you don't.

Here's the quadratic formula:

When the equation is in the form of Ax² + Bx + C = 0

then x = [ -B plus or minus √(B²-4AC) ] / 2A

I'm sure that formula is in your text or your study notes,
right before these questions. You should cut it out or
copy it, and tape it inside the cover of your notebook.
Then, you'll always have it when you need it, until
you have it memorized and can rattle it off.

The first question says 3x² + 5x + 2 = 0

Is this in the form of    Ax² + Bx + C = 0 ?

   Yes !       A=3 B=5   C=2

   so you can use the quadratic formula to solve it.

    x = [ -B plus or minus √(B²-4AC) ] / 2A

   = [ -5 plus or minus √(5² - 4·3·2) ] / 2·3

   = [ -5 plus or minus √(25 - 24) ] / 6

   = [ -5 plus or minus √1    ] / 6

   x =    -4 / 6 = -2/3
and
   x =    -6 / 6 = -1 .
_______________________________________

The second question says

   4x² + 5x - 1 = 0

Is this in the form of Ax² + Bx + C = 0 ?

   Yes it is ! A=4 B=5 C= -1

   so you can use the quadratic formula to solve it.

    x = [ -B plus or minus √(B²-4AC) ] / 2A

Now, you take it from here.

6 0

2 years ago

Use the information to answer the questions.

Anna71 [15]

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) $b^2=a^2+c^2-2(a)(c)cos(B)$