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Vesnalui [34]
3 years ago
8

F(x)=x3−x2 and g(x)=2x+10, then (g ∘ f)(3)=

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Answer:

Step-by-step explanation:

f(3)= 3^3 - 3^2 = 27 - 9 = 18

g(18)= 2(18) + 10 = 36 + 10 = 46

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The area of the shape is 230 cm.

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A line is perpendicular to y = -1/2x-1
brilliants [131]

Answer:

y= 2x -3

Step-by-step explanation:

The first thing you should know is that the slope of a perpendicular line is the opposite reciprocal. So, this is your current equation: y= 2x + b. Next, substitute your point into the equation to get the y-intercept. It should look like this: 9=2(6) + b. 6 times 2 equals 12. Now, this is what it should look like: 9=12 + b. Subtract 12 from both sides to get -3 = b. Go back to your original equation and plug in -3 to b. This is your final equation: y= 2x -3. Hope this helped!

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3 years ago
What is the first quartile of the following data set?<br> 15, 18, 20, 21, 23, 24, 26, 29, 34, 37, 40
nikklg [1K]

Answer:

20.5

Step-by-step explanation:

20 + 21 = 41.   Divide 41 by 2 than you get 20.5.

3 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
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