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3 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!

Mathematics

2 answers:

g100num [7]3 years ago

8 0

Answer:

D. Plane

Step-by-step explanation:

A plane extends in two dimensions. This figure is a plane. It is not a point, a segment or a ray.

PolarNik [594]3 years ago

3 0

Answer:

plane

Step-by-step explanation:

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ALGEBRA 2 PLEASE HELP! QUICKLY!! I AM TERRIBLE AT ALGEBRA AND I HAVE LOADS OF STUFF TO Do TODAY CAN YOU PLEASE HELP ME WITH THIS

Genrish500 [490]

A) the posible roots of the function f(x)=x⁴-3x³-5x²+21x+22 are:
=-1,+1,-2,+2,-11,+11,-22+22.

b)
one zero of the funtion can be: x=-1 ⇒y=0 (-1,0)

c)
other zero of the funtion is: x=-2 ⇒y=0 (-2,0)

d)
if x=0 then y=22 (0,22)

e) In the file is the graph.

4 0

3 years ago

Y>1 and y>x on a graph

zlopas [31]

So,

$y>1\wedge y>x$

1. Graph each inequality separately.

2. Choose a test point to determine which side of the line needs to be shaded.

3. The solution to the system will be the area where the shadings from each inequality overlap one another (purple area)

As for the system of inequalities we say it's unbounded.

3 0

3 years ago

A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win

sveta [45]

Answer:

The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25% of their capacity, how much energy, in kilowatt-hours, can the region's wind farms generate in one year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year

Part B

Given that the average household in the region uses about 10,000 kilowatt-hours of energy each year, how many households can be powered by these wind farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

Amount of households = 4,818'000,000/10,000 = 481,800

8 0

4 years ago

Ashley puts 45 stamps in an album. She puts the same number of stamps on each page,and 3 stamps on the last page. There are 2 mo

ludmilkaskok [199]

45 pages total
3 on last page
45-3=42
there are 42 on the rest of the pages
on each page, there are 2 more pages in album than then stamps on pages

amount of stamps on pages with equal number of stamps is
A=numberofpgest times number of stamps on pages
number of pages=p
number of stamps per papge=s
a=ps

2 more pages than stamps on pages
p=2+s
total number of stamps per page is s=(45-3)/(p-1)
(what I did is I first got rid of number of stamps on last page, then got rid of the last page)
P=2+s
s=(45-3)/(2+s-1)
s=42/(s+1)
times s+1 both sides
s^2+s=42
minus 42
s^2+s-42=0
factor
(s-6)(s+7)=0
set equal to zero
s-6=0
s=6

s+7=0
s=-7, false, no negative stamps

6 stamps per page

sub
p=2+s
p=2+6
p=8
8 pages

check
last page is 3 so 8-1=7 page left

7*6=42
3+42=45

correct

there are
8 pages in the album
6 stamps per page

6 0

3 years ago

If y = kx, where k is a constant, and y = 30 when x = 6, what is the value of y when x = 3?

Svetradugi [14.3K]

Answer:

Step-by-step explanation:

Actually it's 11 because 11 is technically the same when added to constant of x =6 = 11

7 0

3 years ago

SOMEONE PLEASE HELP ME ASAP PLEASE!!!​

SOMEONE PLEASE HELP ME ASAP PLEASE!!!