The average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
<h3>What is the Average Rate of Change of a Function?</h3>
Average rate of change =
.
Given the function,
,
The average rate of change using the intervals of, x = 2 to x = 6 would be solved as shown below:
a = 2
b = 6
f(a) =
= 34
f(b) =
= 754
Average rate of change = 
Average rate of change = 180
Therefore, the average rate of change, of the function, between the intervals, x = 2 to x = 6 is: 180.
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The answer would be: 12 bytes^3
Answer:
For 2a, we are completing the square (see the image below)
To find the stationary point (2b) you change the sign of the number inside the brackets and keep the number outside the same i.e (-2, 7)
Hope this helps!
Answer:
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec
Step-by-step explanation:
Volume V = length l^3
V = x^3
Differentiating both sides;
dV/dt = 3x^2 dv/dt
Given;
x = 10 in
dx/dt = 0.5 in/sec
dV/dt = 3×10^2 × 0.5 = 150 in^3/sec
the volume of the cube is increasing at 150in^3/sec