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e-lub [12.9K]
2 years ago
15

Elijah and Jonathan play on the same soccer team. They have played 3 of their 15 games. They each create a model to represent x,

the number of games their team has left
to play. Their models are shown below. Explain whether each model is correct.

PLS PLS PLS HELP

Mathematics
1 answer:
AlladinOne [14]2 years ago
7 0

what are the optionsss??

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HELP ASAPP !!!<br> A. x=60;y=140<br><br> B. x=60;y=70<br><br> C. x=105;y=95<br><br> D. x=105;y=47.5
SSSSS [86.1K]

Answer:

B

Step-by-step explanation:

Y look like it's close to 90 degrees.

3 0
3 years ago
Which of the following would have a negative impact on determining eligibility for a home loan? a. earning extra income b. movin
storchak [24]

solution:  option D is correct i.e., withdrawing money from savings.

explanation:

if someone is taking home loan then he has to pay it back also. but if he is withdrawing money from savings then he will don't have money to return in future. so he should save as much as he can.

so withdrawing money from savings would have a negative impact on determining eligibility for a home loan.

3 0
2 years ago
HELP PLSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS PLSS I BEFFF
xenn [34]
6:$9
Multiply both by 2 (because 12/6=2)
And get 12:$18

3:7
Multiply both by 2 (because 14/7=2)
And get 6:14

6:3
Multiply both by 8 (48/6=8)
And get 48:24

Always label your units. Sorry I’m lazy

6 0
2 years ago
Someone claims that the average amount of time that a freshman at TAMU studies is 7 hours. We think it’s higher than that and de
Stels [109]

Answer:

Test statistic t = 5.25

P-value = 0.000002 (one-tailed test)

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

Then, the null and alternative hypothesis are:

H_0: \mu=7\\\\H_a:\mu> 7

The significance level is 0.05.

The sample has a size n=49.

The sample mean is M=8.5.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√s^2=√4=2.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{2}{\sqrt{49}}=0.29

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{8.5-7}{0.29}=\dfrac{1.5}{0.29}=5.25

The degrees of freedom for this sample size are:

df=n-1=49-1=48

This test is a right-tailed test, with 48 degrees of freedom and t=5.25, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=P(t>5.25)=0.000002

As the P-value (0.000002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average amount of time that a freshman at TAMU studies is significantly higher than 7 hours.

6 0
2 years ago
X-2y=4 How to solve this
WARRIOR [948]
Since <span>x </span>does not contain the variable to solve for, move it to the right side of the equation by subtracting <span>x</span> from both sides
.−2y=−x+4
divide each term by −2 and simplify.
<span> the answer is y=<span>x/2</span>−<span>2

slope= 1/2
y-intercept = -2</span></span>
4 0
2 years ago
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