check the picture below.
so it has a base of 18x18 and a height of that much.
The minimum distance is the perpendicular distance. So establish the distance from the origin to the line using the distance formula.
The distance here is: <span><span>d2</span>=(x−0<span>)^2</span>+(y−0<span>)^2
</span> =<span>x^2</span>+<span>y^2
</span></span>
To minimize this function d^2 subject to the constraint, <span>2x+y−10=0
</span>If we substitute, the y-values the distance function can take will be related to the x-values by the line:<span>y=10−2x
</span>You can substitute this in for y in the distance function and take the derivative:
<span>d=sqrt [<span><span><span>x2</span>+(10−2x<span>)^2]
</span></span></span></span>
d′=1/2 (5x2−40x+100)^(−1/2) (10x−40)<span>
</span>Setting the derivative to zero to find optimal x,
<span><span>d′</span>=0→10x−40=0→x=4
</span>
This will be the x-value on the line such that the distance between the origin and line will be EITHER a maximum or minimum (technically, it should be checked afterward).
For x = 4, the corresponding y-value is found from the equation of the line (since we need the corresponding y-value on the line for this x-value).
Then y = 10 - 2(4) = 2.
So the point, P, is (4,2).
Answer:
0.54kilometres
Step-by-step explanation:
a)actual distance =2.7*20000
=54000cm
=0.54kilometres
Answer:
<em>-1,3,5,9,13</em>
Step-by-step explanation:
2(-3)+5=-6+5=-1
2(-1)+5=-2+5=3
2(0)+5=0+5=5
2(2)+5=4+5=9
2(4)+5=8+5=13
We know that we are solving for y.
This is a step by step procedure to get the value of y.
First: Move all terms to the left side and set equal to
zero.
Second: Then set each factor equal to zero.
The application is:
Given: py+7=6y+q
-6y -7 -6y -7 = 0
(p-6)y = q-7
divide both sides by p-6
y=(q-7)/(p-6)
Answer is y = (q – 7) / (p – 6)
