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allochka39001 [22]
3 years ago
5

How many counters would you place in the five frame to show the number

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0
Assuming the five frame is for the number five (5) then place 5 counters in the frame.
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What is the gradient of the graph shown? <br><br> Give your answer in its simplest form.
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Answer:

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Step-by-step explanation:

bsdbfhbshfbhfbwhfvcnncsh  jdhsshbfhwapv

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3 years ago
Solve the equation 3x -7 = 5x +19
Nastasia [14]
The first thing you want to do is combine like terms. This means you should have all the x's on one side and the constants (numbers) on the other side. You can subtract 5x from both sides of the equation and then add 7 to both sides. This gives you -2x=26. Divide both sides be -2 to isolate the variable and your answer is x=-13. Hope this helped!
4 0
4 years ago
Read 2 more answers
What is the volume of the cylinder shown below?
Anastasy [175]

<em>here's</em><em> your</em><em> solution</em>

<em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>it </em><em>is </em><em>given </em><em>that</em><em>. </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>height</em><em> </em><em>of </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>1</em><em>5</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>base </em><em>=</em><em> </em><em>9</em><em>u</em><em>n</em><em>i</em><em>t</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> of</em><em> </em><em>cylinder</em><em> </em><em>=</em><em> </em><em>π </em><em>r^</em><em>2</em><em>h</em><em> </em><em>cubic </em><em>unit</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>now,</em><em> </em><em>putting</em><em> the</em><em> value</em><em> of</em><em> </em><em>height</em><em> and</em><em> </em><em>radius </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>in </em><em>above </em><em>formula </em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>2</em><em>2</em><em>/</em><em>7</em><em> </em><em>*</em><em>9</em><em>*</em><em>9</em><em>*</em><em>1</em><em>5</em>

<em> </em><em> </em><em> </em><em> </em><em>=</em><em>></em><em> </em><em>volume</em><em> </em><em>=</em><em> </em><em>3</em><em>6</em><em>1</em><em>7</em><em>7</em><em>c</em><em>u</em><em>b</em><em>i</em><em>c</em><em> </em><em>unit</em>

4 0
3 years ago
Ariah Janson
Ivan

Answer:

Root: (8/3,0)

Step-by-step explanation:

7 0
3 years ago
Determine which of the following are equivalence relations and/or partial ordering relations for the given sets: A = { lines in
VLD [36.1K]

Answer:

Check the explanation

Step-by-step explanation:

1

a) A is an Equivalence Relation

Reflexive : x is parallel to itself => x R x

Symmetric : x is parallel to y => y is parallel to x.

Therefore x R y => y R x

Transitive :  x is parallel to y and y is parallel to z then x, y, z are parallel to each other.

=> x R y and y R z => x R z

Therefore A is equivalent.

1. b)

x r y if and only if |x-y| less than or equal to 7

Reflexive : |x-x| = 0 <= 7 => x R x Satisfied.

Symmetric : let x R y => |x-y| <= 7

Consider |y-x| = |(-1)*(x-y)| = |x-y| <= 7

=> y R x => Satisfied

Transitive : let x R y and y R x

=> |x-y| <= 7 and |y-z| <= 7

but this doesn't imply x R z

Counter-Example : x = 1, y = 7, z = 10

Therefore this relation is neither Equivalent nor Partial Order Relation.

8 0
3 years ago
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