The <em>dot</em> product associated to sides AB and BC is 0.
<h3>What is the dot product generated by two sides of a triangle?</h3>
In this question we must find the <em>dot</em> product of two vectors associated with two surrounding sides of a triangle. First, we need to find the vectors associated to sides AB and BC:
Side BA
<u>BA</u> = (5, 3) - (0, 0)
<u>BA</u> = (5, 3)
Side BC
<u>BC</u> = (- 3, 5) - (0, 0)
<u>BC</u> = (- 3, 5)
By definition of <em>dot</em> product, the result associated to the two sides of the triangle is:
<u>BA</u> • <u>BC</u> = (5, 3) • (- 3, 5)
<u>BA</u> • <u>BC</u> = (5) · (- 3) + (3) · (5)
<u>BA</u> • <u>BC</u> = - 15 + 15
<u>BA</u> • <u>BC</u> = 0
The <em>dot</em> product associated to sides AB and BC is 0.
<h3>Remark</h3>
The statement is poorly formatted, the correct form is shown below:
If A(x, y) = (5, 3), B(x, y) = (0, 0) and C(x, y) = (- 3, 5) are the vertices of a triangle then the value of the dot product between vectors AB and BC is:
To learn more on dot product: brainly.com/question/14455586
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