This looks like an ellipse.
Complete the square for y: 9(y²-6y-7)=9(y²-6y+9-9-7)=9((y-3)²-16).
Rewrite the equation:
4x²+9(y-3)²-144=0; 4x²/144+9(y-3)²/144=1; x²/36+(y-3)²/16=1.
Standard equation of an ellipse is (x-h)²/a²+(y-k)²/b²=1, where (h,k) is the origin or centre.
This is the equation of an ellipse with centre (0,3), a=6 and b=4 (semimajor and semiminor axes).
Answer:
1) A = 27 square units, P = 24 units; 2) 276 mm; 3) A = 8, B = 4, C = 3, D = 5, 108 square feet; 4) 5.
Step-by-step explanation:
1) The sides of the rectangle are 9, 9, 3, and 3.
2) 40 + 40 + 70 + 70 + 28 + 28
3) 32 + 6 + 6 + 24 + 40 = 108
4) 24 + 24 + 20 + 20 + 30 + 30 = 148
740/148 = 5
Let A unit be a; B unit be b
a + b = 95
b = 95 - a
3a + 5b = 395
3a + 5(95 -a) = 395
3a + 475 - 5a = 395
-2a = -80
a = 40
a + b = 95
40 + b = 95
b = 55
Therefore, a = 40; b = 55.
Hope this helps
Answer:
(3, 3 )
Step-by-step explanation:
Given the 2 equations
3x - y = 6 → (1)
6x + y = 21 → (2)
Adding the 2 equations term by term will eliminate y, that is
(6x + 3x) + (y - y) = (21 + 6), that is
9x = 27 (divide both sides by 9 )
x = 3
Substitute x = 3 into either (1) or (2) and solve for y
Using (2), then
(6 × 3) + y = 21
18 + y = 21 ( subtract 18 from both sides )
y = 3
Solution is (3, 3 )
X + y = 22
x = 3y + 2
3y + 2 + y = 22
4y + 2 = 22
4y = 22 - 2
4y = 20
y = 20/4
y = 5
x = 3y + 2 = 3(5) + 2 = 15 + 2 = 17
ur numbers are 5 and 17
