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maxonik [38]
4 years ago
6

A group of five people are selected at random. What is the probability that two of them were born on the same day of the week? (

Assume that a person is equally likely to be born on any day of the week.)
Mathematics
1 answer:
alexdok [17]4 years ago
3 0

Answer:

50/50 chance

Step-by-step explanation:

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If your gonna answer thanks
muminat

Answer:

Step-by-step explanation:

Its c the answer

3 0
3 years ago
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Doris paid $316.80 for wallpaper to cover a 24 foot by 12 foot wall. She used all the wallpaper she purchased, with no waste or
tatiyna
The answer is $1.10 because if you divide and multiply by the other answers this answer is the only one that makes sense
4 0
3 years ago
What is the area of the piece of red paper after the hole for
MakcuM [25]

Answer:

     \large\boxed{\large\boxed{47unit^2}}

Explanation:

The complete question is:

<em>A hole the size of a photograph is cut from a red piece of paper to use in a picture frame.</em>

<em />

<em>On a coordinate plane, 2 squares are shown. The photograph has points (-3, -2), (- 2, 2), (2, 1), and (1, -3). The red paper has points (- 4, 4), (4, 4), (4, -4), and (-4, -4).</em>

<em />

<em>What is the area of the piece of red paper after the hole for the photograph has been cut?</em>

<em />

<h2><em>Solution</em></h2>

<em />

The area of the piece of redpaper after the hole has been cut is equal to the area of the big square less the area of the small rectangle.

<u>1. Area of the big rectangle</u>

Vertices:

  • <em>(- 4, 4) </em>
  • <em>(4, 4)</em>
  • <em>(4, -4)</em>
  • <em>(-4, -4)</em>

<em />

The side length is the distance between two consecutive vertices:

The two points (-4,4) and (4,4) has the same y-coordinate, thus the length is just the absolute value of the difference of the x-coordinates:

  • 4-(-4)=4+4=8

The area of this square is    (8unit)^2=64unit^2

<u>2. Area of the small square</u>

Vertices:

  • <em>(-3, -2)</em>
  • <em>(- 2, 2) </em>
  • <em>(2, 1)</em>
  • <em>(1, -3)</em>

<em />

To find the side length use the distance formula for two consecutive points, for instance (2,1) and (-2,2):

      d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}\\ \\d=\sqrt{(2-(-2))^2+(2-1)^2}=\sqrt{4^2+1^2}=\sqrt{17}

The area is:

          (\sqrt{17}unit)^2}=17unit^2

<u>3. Area of the piece of red paper after the holw for the photograph has been cut:</u>

<u />

Find the difference:

<u />

         64unit^2-17unit^2=47unit^2

<em />

7 0
4 years ago
Read 2 more answers
Determine the interquartile range for the given data 11, 13, 16, 17, 8, 10, 14, 14, 17, 14
Elanso [62]

Answer:

<em>(IQR) interquartile range: 4.5!</em>

Step-by-step explanation:

8, 10, 11, 13, 14, 14, 14, 16, 17

Median: 14

Lower quartile: 10.5

Upper quartile: 15

Interquartile range: 15 - 10.5 = 4.5

7 0
3 years ago
I need help with this question. Question is in image below. ​
ExtremeBDS [4]

Answer:

A. Answer is 2263.

Checkpoint 1 is -86 Checkpoint 4 is 2177

Subtract -86 from 2177....2177-(-86)   

=2263

2263 is how much higher checkpoint 1 (-86) is from checkpoint 4 (2177)

B. 239 FEET.

the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)

therefore the altitude of the hill comes out to be 428-189=239feet.

therefore,the actual altitude of the hill is 239 feet.

7 0
2 years ago
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