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3 years ago

Logan takes 8.95 minutes to run 1 mile.

Mathematics

2 answers:

abruzzese [7]3 years ago

8 0

Answer:

It will take him 39.0425 ≈ 39 minutes to run 4.85 miles.

Step-by-step explanation:

All we have to do is multiply 8.05 by 4.85. So:

8.05 × 4.85 = 39.0425

Delicious77 [7]3 years ago

8 0

Answer:

43.40minutes

Step-by-step explanation:

8.95*4.85=43.4075

if this is correct can i get brainliest

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Would you use an open circle or a closed circle to graph the inequality x> 3?

12345 [234]

Answer:

Open circle

Step-by-step explanation:

If the inequality has < or > it is an open circle.

If the inequality has =< or >= it is closed

Have A Great day

8 0

4 years ago

Read 2 more answers

Y = 5-3x, Darw the graph of the function. Use the find the value of y when x=4, and when x = 5

stellarik [79]

Answer:

The line passes through (4, -7) and (5, -10).

Step-by-step explanation:

When x = 4, y = 5 - 3(4), or 5 - 12, or -7. Thus the point (4, -7) lies on the graph. Similarly y = 5 - 3(5) = -10 when x = 5. Thus, the line also goes through (5, -10). Plot these two points and draw a line through them. Doing this will result in the desired graph.

6 0

2 years ago

Water is leaking out of a large barrel at a rate proportional to the square rooot of the depth of the water at that time. If the

sdas [7]

Answer:

It will take about 35.49 hours for the water to leak out of the barrel.

Step-by-step explanation:

Let $y(t)$ be the depth of water in the barrel at time $t$ , where $y$ is measured in inches and $t$ in hours.

We know that water is leaking out of a large barrel at a rate proportional to the square root of the depth of the water at that time. We then have that

$\frac{dy}{dt}=-k\sqrt{y}$

where $k$ is a constant of proportionality.

Separation of variables is a common method for solving differential equations. To solve the above differential equation you must:

Multiply by $\frac{1}{\sqrt{y}}$

$\frac{1}{\sqrt{y}}\frac{dy}{dt}=-k$

Multiply by $dt$

$\frac{1}{\sqrt{y}}\cdot dy=-k\cdot dt$

Take integral

$\int \frac{1}{\sqrt{y}}\cdot dy=\int-k\cdot dt$

Integrate

$2\sqrt{y}=-kt+C$

Isolate $y$

$y(t)=(\frac{C}{2} -\frac{k}{2}t)^2$

We know that the water level starts at 36, this means $y(0)=36$ . We use this information to find the value of $C$ .

$36=(\frac{C}{2} -\frac{k}{2}(0))^2\\C=12$

$y(t)=(\frac{12}{2} -\frac{k}{2}t)^2\\\\y(t)=(6 -\frac{k}{2}t)^2$

At t = 1, y = 34

$34=(6 -\frac{k}{2}(1))^2\\k=12-2\sqrt{34}$

So our formula for the depth of water in the barrel is

$y(t)=(6 -\frac{12-2\sqrt{34}}{2}t)^2\\\\y(t)=\left(6-\left(6-\sqrt{34}\right)t\right)^2\\$

To find the time, $t$ , at which all the water leaks out of the barrel, we solve the equation

$\left(6-\left(6-\sqrt{34}\right)t\right)^2=0\\\\t=3\left(6+\sqrt{34}\right)\approx 35.49$

Thus, it will take about 35.49 hours for the water to leak out of the barrel.

5 0

4 years ago

If the half-life of a radioactive substance is 2,800 years, then at what rate is it decaying?

vlada-n [284]

Answer:

0.0001075

Step-by-step explanation:

The relation between halflife and rate at which it is decaying is given by

$t_{\frac{1}{2} } =\dfrac{log2}{rate}$

now in the above problem halflife is given as 2800 years substituting in the above equation we get the value of rate at which it is decaying to be rate=0.0001075.

6 0

3 years ago

Please help guys. And if u can help me with this topic farther pls message me for the ig or snap

Setler [38]

Answer:

Step-by-step explanation:

108 divided by 2 is 54 making the value of y 4. Hope this helps!

8 0

3 years ago