Answer:
ok so what i think your trying to ask is if we roll two dice that the sum will be more then 6
Two dice
Assuming that the dice are unbiased or not " loaded".
Each side has the same probability, is 1/6 =0.16667, to turn up when rolled, if the die (D) is unbiased. The probability of a side turning up on D1 when 2 dice ( D1,D2) are rolled, is independent of the side turning up in D2. So this is an independent event.
How many ways can one get a sum total of 6 if D1 &D2 are rolled at the same time?
These are the possibilities
Case 1.
D1 =1 & D2=5
Or
D1= 5 & D2=1
Case 2.
D1 =2 & D2=4
Or
D1= 4 & D2= 2
Case 3. D1=3, D2=3
P3 =0.027778
Let's say, P 1 the probability for case 1 and P2 for case 2. There are no other cases.
The final probability P and is the sum total P = P1 + P2 + P3 the probability law of mutually exclusive events.
P1= 0.02778+ 0.02778 =0.055558
P2= 0.02778+0.02778 =0.055558
Same way,
P3=0.027778, when there is only one way to get the sum 6.
So, P = 0.138894
Based on truncating at the sixth decimal place.
A visual representation with two unbiased dice and the possible cases would also give the same result and is a short cut method. I like to derive from the basics.
Hope This Helps!!!
