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Finger [1]
3 years ago
9

What angle is included by segments AB and AC

Mathematics
2 answers:
myrzilka [38]3 years ago
4 0

Answer:

Angle A is included by segments AB and AC.    

Step-by-step explanation:

Please find the attachment.

We are asked to determine the angle that is included by segments AB and AC.

We can see that segment AB and AC have the common point A, so these segments will form angle A.

Therefore, \angle A is included angle by side AB and AC.

BabaBlast [244]3 years ago
3 0
It's angle A fam!!!!!!!!!!!!!!!!!!!!!!!!
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Answer:

70%

Step-by-step explanation:

=10.50/35.00%

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=100%-30%

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Points P, Q and R are collinear such that PQ : QR=2:3 point P is located at (1,3) and point R is located at (11,15)
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Using line segments, it is found that:

  • The coordinates of Q are (5,7.8).
  • The midpoint of segment PQ is M(6,9).

----------------------------

  • Point P is located at (1,3).
  • Point R is located at (11,15).
  • Point Q is located at (x,y).
  • PQ:QR = 2:3, which means that:

Q - P = \frac{2}{5}(R - P)

This is used to find the x and y coordinates of Q.

----------------------------

  • The <em>x-coordinate</em> of P is 1.
  • The <em>x-coordinate</em> of R is 11.
  • The <em>x-coordinate </em>of Q is x.

Thus:

Q - P = \frac{2}{5}(R - P)

x - 1 = \frac{2}{5}(11 - 1)

x - 1 = \frac{2}{5}10

x - 1 = 4

x = 5

----------------------------

  • The y<em>-coordinate</em> of P is 3.
  • The y<em>-coordinate</em> of R is 15.
  • The y<em>-coordinate </em>of Q is y.

Thus:

Q - P = \frac{2}{5}(R - P)

y - 3 = \frac{2}{5}(15 - 3)

y - 3 = \frac{24}{5}

y - 3 = 4.8

y = 7.8

The coordinates of Q are (5,7.8).

----------------------------

  • The midpoint of segment PQ is the mean of the coordinates, thus:

M = (\frac{1 + 11}{2}, \frac{3 + 15}{2}) = (\frac{12}{2}, \frac{18}{2}) = (6,9)

The midpoint of segment PQ is M(6,9).

A similar problem is given at brainly.com/question/24148182

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