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3 years ago

Identify Population Parameters From Sample Statistics

Mathematics

1 answer:

Anika [276]3 years ago

4 0

Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:vvAnswer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:vAnswer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:vvAnswer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:Answer:

(x−2)(x−2)(x−2)

Step-by-step explanation:v

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OleMash [197]

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= 1/2*6*16

=3*16

= 48 yd²

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3 years ago

Find the volume of the rectangular prism<br> Thank you!!

Brrunno [24]

Answer:90

Step-by-step explanation: do length x base x height to get your answer

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3 years ago

Suppose that in a casino game the payout is a random variable X . If X is positive, you gain money, if negative, you lose.

Vanyuwa [196]

Answer:

the conditional probability that X = 1 , X = 2 and X = 3 is 0.7333 (73.33%) , 0.25 (25%) and 0.0167 (1.67%) respectively

Step-by-step explanation:

a player wins money when i>0 then defining event W= gain money , then

P(W) = p(i>0) = p(1)+p(2)+p(3)

then the conditional probability can be calculated through the theorem of Bayes

P(X=1/W)= P(X=1 ∩ W)/P(W)

where

P(X=1 ∩ W)= probability that the payout is 1 and earns money

P(X=1 / W)= probability that the payout is 1 given money was earned

then

P(X=1/W)= P(X=1 ∩ W)/P(W) = P(X=1) / P(W) = p(1) /[p(1)+p(2)+p(3)] = 11/40 /(11/40+3/32+1/160 ) = 0.7333 (73.33%)

similarly

P(X=2/W)=p(2) /[p(1)+p(2)+p(3)] = 3/32 /(11/40+3/32+1/160 ) = 0.25 (25%)

P(X=3/W)=p(2) /[p(1)+p(2)+p(3)] = 1/160 /(11/40+3/32+1/160 ) = 0.0167 (1.67%)

8 0

4 years ago

I NEED HELP WITH THIS ASAP!

horrorfan [7]

I think it’s the 1st one because it’s close too what it is when I work it out

7 0

3 years ago

According to a study conducted by an organization, the proportion of Americans who were afraid to fly in 2006 was 0.10. A rando

Nimfa-mama [501]

Answer: No, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

Step-by-step explanation:

Since we have given that

n = 1400

x = 154

So, $\hat{p}=\dfrac{154}{1400}=0.11$

and p = 0.10

So, hypothesis would be

$H_0:\hat{p}=p\\\\H_a:\hat{p}>p$

So, the test statistic value would be

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\z=\dfrac{0.11-0.10}{\sqrt{\dfrac{0.1\times 0.9}{1400}}}\\\\z=\dfrac{0.01}{0.008}\\\\z=1.25$

At 5% level of significance,

critical value would be 1.96.

Since 1.96>1.25.

so, we will accept the null hypothesis.

Hence, no, this is not necessarily evidence that the proportion of Americans who are afraid to fly has increased.

3 0

3 years ago