Pamela owns 15 T-shirts, 3 of which are yellow.

A cardboard box is open at one end and it's shaped like a square prism missing one of its Square bases the volume of the prism i

Andru [333]

A = 9 inches
B = 441 inches squared

3 0

2 years ago

Donna Meagle notices that on 12 out of 14 days, her clumsy coworker Jerry Gergich spills his lunch on himself. She concludes tha

pantera1 [17]

Answer:

It is an example of an empirical probability.

Step-by-step explanation:

The empirical probability, also called experimental probability of an event is the ratio of the number of outcomes in which a specified event occurs to the total number of trials, not in a theoretical sample space but in an actual experiment.

Theoretical probability is probability that is determined on the basis of reasoning.

It is evident that the probability in the question was arrived at after the outcome of 14 days of whether Jerry Gergich spilled his lunch on himself or not.

It's an actual result of an experiment, hence the 12/14 = 0.86 = 86% that he spills his lunch on himself tomorrow.

Hope this Helps!!!

6 0

3 years ago

Suppose XY is parallel to segment X’Y’is triangle OXY similar to Ox’Y’ explain please

faust18 [17]

yes it is a smaller diagram than the angle o x y

8 0

2 years ago

The overhead reach distances of adult females are normally distributed with a mean of 205 cm and a standard deviation of 7.8 cm.

devlian [24]

Answer:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z $\leq 1.72$ ). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z $\leq -1.09$ ). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

Step-by-step explanation:

Given the mean = 205 cm and standard deviation as 7.8cm

a. To calculate the probability that an individual distance is greater than 218.4 cm, we subtract the probability of the distance given (i.e 218.4 cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) from 1. Therefore, we have 1- P(Z $\leq 1.72$ ). Using the Z distribution table we have 1-0.9573. Therefore P(X >218.4)= 0.0427.

b. To calculate the probability that mean of 15 (i.e n=15) randomly selected distances is greater than 202.8, we subtract the probability of the distance given (i.e 202.8cm) from the mean (i.e 205 cm) divided by the standard deviation (i.e 7.8cm) divided by the square root of mean (i.e n= 15) from 1. Therefore, we have 1- P(Z $\leq -1.09$ ). Using the Z distribution table we have 1-0.1378. Therefore P(X >202.8)= 0.8622.

c. This will also apply to a normally distributed data even if it is not up to the sample size of 30 since the sample distribution is not a skewed one.

4 0

3 years ago

How can you use ratios to convert units of measurement

Yuliya22 [10]

You do
unit of measurement you are using (should be one for now): unit of measurement you want to convert it to.
next you put your measurement in the first one and make the second one your measurement multiplied by whatever your measurement is

3 0

3 years ago