Answer: option c
length = 9m
Perimeter = 26.4m
Step-by-step explanation:
A rectangle has a width of 4.2 m and an area of 37.8 m^2
We want yo determine the length of the rectangle and the perimeter of the rectangle.
The perimeter of the rectangle is the distance round the shape. Let the width of the triangle be w.
The perimeter of the rectangle would be expressed as Length + width + length + width. This becomes
2(length +width). So the perimeter of the given rectangle is
2(length + 4.2) but the area is given as 37.8 m^2. Area of a rectangle is length × width. It becomes
37.8= length × 4.2
Length = 37.8/4.2 = 9m
Therefore, the perimeter is
2(length + 4.2) = 2(9+4.2)
Perimeter = 2× 13.2 = 26.4m
the distance between points is:
d = 7.8 units
d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
The ordered pairs are:
(x1, y1) = (- 3, -2)
(x2, y2) = (2,4)
By applying the formula we have:
d = root ((2 - (- 3)) ^ 2 + (4 - (- 2)) ^ 2)
d = root (61)
d = 7.8
Answer:
The legs of a 45 45 90 triangle are congruent so if one leg is x we can write (using the Pythagorean Theorem):
x² + x² = 18²
2x² = 324
x² = 162
x = 9√2
The quadratic formula is above.
You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3
Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a