Model to write 30 or 40 as a mixed number

52% of all Americans are home owners. If 45 Americans are randomly selected, find the probability that a. Exactly 21 of them are

Nataly [62]

Answer:

0.0918 ; 0.6277 ; 0.6064; 0.5055

Step-by-step explanation:

Given that :

Proportion of home owners : p = 0.52

Number of trials = 45

Using binomial distribution formula :

P(x =x) = nCr * p^x * (1 - p)^(n-x)

A.) probability that exactly 21 are homeowners :

P(x = 21) = 45C21 * 0.52^21 * (1 - 0.52)^(45 - 21)

P(x = 21) = 45C21 * 0.52^21 * 0.48^24

P(x = 21) = 3773655750150 * 0.52^21 * 0.48^24

P(x = 21) = 0.0918

b. At most 24 of them are are home

Using the binomial probability to save computation time.

P(x ≤ 24) = p(0) + p(1) +.... + p(24)

P(x ≤ 24) = 0.6277

C.) At least 23 of them are home owners.

P(x ≥ 23) = p(23) + p(24) +... + p(45)

P(x ≥ 23) = 0.6064

d. Between 20 and 24 (including 20 and 24) of them are home owners.

P(20 ≤ x ≤ 24) = p(20) + p(21) + p(22) + p(23) + p(24)

P(20 ≤ x ≤ 24) = 0.0711 + 0.0918 + 0.1084 + 0.1175 + 0.1167

P(20 ≤ x ≤ 24) = 0.5055

8 0

3 years ago

Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br

olga2289 [7]

Since F=m•a, you want to show that a = -5.5

5 0

3 years ago

Read 2 more answers

The instructions are:

Darina [25.2K]

Comment if you need clarification!

5 0

4 years ago

Find the product of 28 and 4. ONLY type in the number.

Jet001 [13]

Answer: 112

Step-by-step explanation:

8 0

3 years ago

In a school machine shop, 60% of all machine breakdowns occur on lathes and 15% occur on drill presses. Let E denote the event t

RSB [31]

Answer:

A. P(EC) = 0.4

B. P(E∪E) = 0.75

C. P(EC ∩ FC) = 0.25

Step-by-step explanation:

Let us calculate -:

we are given with - P(E) = 60 and P(F) =.15,

Thus , (a) $P(E^C)=1-P(E)$

$=1-0.6$

$=0.4$

(b) P(E∪F) = P(E) + P(F)

= 0.60 + 0.15

= 0.75

(c) $P(E^C$ ∩ $F^C)$ $=1-P(E$ ∪ $F)$

$=1-0.75$

= $0.25$

Hence , the answers are -A. P(EC) = 0.4 , B. P(E∪E) = 0.75 , C. P(EC ∩ FC) = 0.25.

6 0

3 years ago