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3 years ago

A polygon has 7 sides. What is the sum of the measure of the exterior angles of the polygon?

Mathematics

2 answers:

Mariulka [41]3 years ago

5 0

I think it's C, 360 degrees.

zysi [14]3 years ago

5 0

A polygon always has exterior angles adding up to 360*.

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Find the area of the composite figure.

Roman55 [17]

Answer:

The Area of the composite figure would be 76.26 in^2

Step-by-step explanation:

According to the Figure Given:

Total Horizontal Distance = 14 in

Length = 6 in

To Find :

The Area of the composite figure

Solution:

Firstly we need to find the area of Rectangular part.

So We know that,

$\boxed{ \rm \: Area \: of \: Rectangle = Length×Breadth}$

Here, Length is 6 in but the breadth is unknown.

To Find out the breadth, we’ll use this formula:

$\boxed{\rm \: Breadth = total \: distance - Radius}$

According to the Figure, we can see one side of a rectangle and radius of the circle are common, hence,

$\longrightarrow\rm \: Length \: of \: the \: circle = Radius$

Since Length = 6 in ;

$\longrightarrow \rm \: 6 \: in = radius$

Hence Radius is 6 in.

So Substitute the value of Total distance and Radius:

Total Horizontal Distance= 14
Radius = 6

$\longrightarrow\rm \: Breadth = 14-6$

$\longrightarrow\rm \: Breadth = 8 \: in$

Hence, the Breadth is 8 in.

Then, Substitute the values of Length and Breadth in the formula of Rectangle :

Length = 6
Breadth = 8

$\longrightarrow\rm \: Area \: of \: Rectangle = 6 \times 8$

$\longrightarrow \rm \: Area \: of \: Rectangle = 48 \: in {}^{2}$

Then, We need to find the area of Quarter circle :

We know that,

$\boxed{\rm Area_{(Quarter \; Circle) } = \cfrac{\pi{r} {}^{2} }{4}}$

Now Substitute their values:

r = radius = 6
π = 3.14

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 6 {}^{2} }{4}$

Solve it.

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times 36}{4}$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = \cfrac{3.14 \times \cancel{{36} } \: ^{9} }{ \cancel4}$

$\longrightarrow\rm Area_{(Quarter \; Circle)} =3.14 \times 9$

$\longrightarrow\rm Area_{(Quarter \; Circle) } = 28.26 \: {in}^{2}$

Now we can Find out the total Area of composite figure:

We know that,

$\boxed{ \rm \: Area_{(Composite Figure)} =Area_{(rectangle)}+ Area_{ (Quarter Circle)}}$

So Substitute their values:

$\rm Area_{(rectangle)}$ = 48
$\rm Area_{(Quarter Circle)}$ = 28.26

$\longrightarrow \rm \: Area_{(Composite Figure)} =48 + 28 .26$

Solve it.

$\longrightarrow \rm \: Area_{(Composite Figure)} =\boxed{\tt 76.26 \:\rm in {}^{2}}$

Hence, the area of the composite figure would be 76.26 in² or 76.26 sq. in.

$\rule{225pt}{2pt}$

I hope this helps!

3 0

2 years ago

CS Algebra

CaHeK987 [17]

Answer:

Hope this helps :)

Step-by-step explanation:

8(x - 2) = 2x + 8

y+9 = -2(y + 1)

value of x in 8(x - 2) = 2x + 8

x=4

substitue

y+9=−2(y+1)

value of y y+9=−2(y+1)

y= - 11/3 or 3.66...

x=4

y=4 (I rounded 3.66)

4 0

2 years ago

When it says graph the image, it's asking me to graph a reflection across x = -2. what's the answer look like?

uranmaximum [27]

The reflection across x = -2 will be x = 2.

8 0

2 years ago

Solve<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D" id="TexFormula1" title="\frac{2}{3}" alt="\frac{2}{3}" align="absm

Dovator [93]

Answer:

$x=0$

Step-by-step explanation:

Hi there!

$\displaystyle\frac{2}{3} (6x+30)=5(x+4)-2x$

Distribute 2/3 and 5 into the parentheses:

$4x+20=5x+20-2x$

Combine like terms:

$4x-5x+2x=20-20\\-x=0\\x=0$

I hope this helps!

7 0

2 years ago

Please help help help help help please ASAP

lora16 [44]

Answer

~~~~~~~~~~~~

slope: 1

y intercept: 4

equation: y=x+4

6 0

2 years ago