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Complete the set of ordered pairs for the relation.

neonofarm [45]

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

<h3>How to complete the set of ordered pairs?</h3>

Here we have the relation:

y = 2*|x + 1|

And the domain is x ∈ { -2, -1, 0, 1, 2}

Evaluating in the values of the domain, we get:

if x = -2.

y = 2*|-2 + 1| = 2

Then we have the ordered pair (-2, 2)

if x = -1

y = 2*|-1 + 1| = 0

Then we have the ordered pair (-1, 0)

if x = 0

y = 2*|0 + 1| = 2

Then we have the ordered pair (0, 2)

if x = 1

y = 2*|1 + 1| = 4

Then we have the ordered pair (1, 4)

if x = 2

y = 2*|2 + 1| = 6

Then we have the ordered pair (2, 6)

The set of ordered pairs is:

{(-2, 2), (-1, 0), (0, 2), (1, 4), (2, 6)}

If you want to learn more about ordered pairs:

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6 0

1 year ago

(4x-1) /2=x+7 4x-1 all over 2 = x +7

Damm [24]

Answer:

x = $\frac{15}{2}$

Step-by-step explanation:

Given

$\frac{4x-1}{2}$ = x + 7 ( multiply both sides by 2 to clear the fraction )

4x - 1 = 2(x + 7) ← distribute

4x - 1 = 2x + 14 ( subtract 2x from both sides )

2x - 1 = 14 ( add 1 to both sides )

2x = 15 ( divide both sides by 2 )

x = $\frac{15}{2}$

7 0

2 years ago

Given: cos θ=-4/5, sin x = -12/13, θ is in the third quadrant,

USPshnik [31]

By definition of tangent,

tan(2θ) = sin(2θ) / cos(2θ)

Recall the double angle identities:

sin(2θ) = 2 sin(θ) cos(θ)

cos(2θ) = cos²(θ) - sin²(θ) = 2 cos²(θ) - 1

where the latter equality follows from the Pythagorean identity, cos²(θ) + sin²(θ) = 1. From this identity we can solve for the unknown value of sin(θ):

sin(θ) = ± √(1 - cos²(θ))

and the sign of sin(θ) is determined by the quadrant in which the angle terminates.

We're given that θ belongs to the third quadrant, for which both sin(θ) and cos(θ) are negative. So if cos(θ) = -4/5, we get

sin(θ) = - √(1 - (-4/5)²) = -3/5

Then

tan(2θ) = sin(2θ) / cos(2θ)

tan(2θ) = (2 sin(θ) cos(θ)) / (2 cos²(θ) - 1)

tan(2θ) = (2 (-3/5) (-4/5)) / (2 (-4/5)² - 1)

tan(2θ) = 24/7

4 0

3 years ago

What two numbers have a sum of -7 and a difference of 14?

Ksivusya [100]

Answer:

The sum of two numbers is 14 and their difference is 10

Step-by-step explanation:

"2 numbers (x and y)

x+y = 14

and x-y + 10

If you each equation by positive 2, one gets 2x+2y = 28 and 2x-2y = 20

The 'y-terms' cancel out or equal zero when adding, so 4x = 48, divide by 4 on each side and x or the first number equals 12.

Plug 12 back into the equation for 'x' and subtract 12 on both sides so that y=2

The difference of 12-2=10 and the addition of 12 and 2 equals 14"

hopes this helps

7 0

2 years ago

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WILL GIVE BRAINLIEST! Please help me quickly with math!

Inga [223]

4 units hope this helps

8 0

3 years ago

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