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Alik [6]
3 years ago
14

Which expression is equivalent to -8?

Mathematics
2 answers:
Free_Kalibri [48]3 years ago
8 0

Answer:

(-\frac{1}{2} )^{-3}

Step-by-step explanation:

Let us apply the following law of exponents to simplify all the options.

a^{-m}=\frac{1}{a^{m}}


For the first option, we have

-2^{-3}=\frac{1}{-2^3} =-\frac{1}{2\times 2\times 2\times 2} =-\frac{1}{8}


For the second expression, we have,


(-\frac{1}{2})^{-3}=\frac{1}{(-\frac{1}{2})^3}


=\frac{1}{-\frac{1}{2}\times -\frac{1}{2} \times -\frac{1}{2} }


=\frac{1}{-\frac{1}{8} }


=-1\times \frac{8}{1}=-8


For the third expression, we have,


(\frac{1}{2})^{-3}=\frac{1}{(\frac{1}{2})^3}


=\frac{1}{\frac{1}{2}\times \frac{1}{2} \times \frac{1}{2} }


=\frac{1}{\frac{1}{8} }


=1\times \frac{8}{1}=8


For the last option, we have

2^{-3}=\frac{1}{2^3} =\frac{1}{2\times 2\times 2\times 2} =\frac{1}{8}


Hence the correct answer is B.

Ronch [10]3 years ago
7 0

Answer:

The answer is B,

Step-by-step explanation:

I got it right on the test

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Answer:

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Step-by-step explanation:

Given:

Total number of classes = 9

Number of student in each class = 25

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Number of chaperones = Double of teacher

Bus hold = 45 people

Find:

Least number of bus require for trip

Computation:

Total number of student = 9 × 25

Total number of student = 225

Number of chaperones = 4 × 2

Number of chaperones = 8

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6 0
2 years ago
Shopping at Savers Mart, Lisa buys her children 4 shirts and 3 pairs of pants for $85.50. She returns the next day and buys 3 sh
maria [59]

Answer:

price for one shirt

=

$

7.50

price for one pair of pants

=

$

18.50

Explanation:

Start by letting variables

x

and

y

represent the pieces of clothing from the problem.

Let

x

be the price of one shirt.

Let

y

be the price of one pair of pants.

Equation

1

:

4

x

+

3

y

=

85.50

Equation

2

:

3

x

+

5

y

=

115.00

You can solve for each variable by using elimination or substitution. However, in this case, we will use use elimination. First, we will solve for

y

, the price of each pair of pants.

To isolate for

y

, we must eliminate

x

. We can do this by making the two equations have the same

x

values. First, we find the LCM of

4

and

3

, which is

12

. Next, multiply equation

1

by

3

and equation

2

by

4

so that

4

x

and

3

x

becomes

12

x

in both equations.

Equation

1

:

4

x

+

3

y

=

85.50

3

(

4

x

+

3

y

)

=

3

(

85.50

)

12

x

+

9

y

=

256.50

Equation

2

:

3

x

+

5

y

=

115.00

4

(

3

x

+

5

y

)

=

4

(

115.00

)

12

x

+

20

y

=

460.00

Now that we have two equations with

12

x

, we can subtract equation

2

from equation

1

to solve for

y

.

12

x

+

9

y

=

256.50

12

x

+

20

y

=

460.00

−

11

y

=

−

203.50

y

=

18.50

⇒

price for one pair of pants

Now that we know that a pair of pants is

$

18.50

, we can substitute this value into either equation

1

or

2

to find price for one shirt. In this case, we will choose equation

1

.

4

x

+

3

y

=

85.50

4

x

+

3

(

18.50

)

=

85.50

4

x

+

55.5

=

85.50

4

x

=

28

x

=

7.50

⇒

price for one shirt

∴

, the price for one shirt is

$

7.50

and the price for one pair of pants is

$

18.50

.

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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