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natka813 [3]
3 years ago
11

What is the probability of getting either a nine or an ace when drawing a single card from a deck of 52​ cards?

Mathematics
1 answer:
Flura [38]3 years ago
8 0

probability of drawing ace: 4/52 = 1/13

probability of drawing 9: 4/52 = 1/13

probability of drawing ace or 9: 1/13 + 1/13 = 2/13 or ~15.4%

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Mr. Robinson has 20 students in his martial arts class. The ratio of boys to girls is 4:1. How many boys and girls are in Mr. Ro
svlad2 [7]
1) Ratio - 4:1

thus, 4x + 1x = 20
5x = 20

thus, x = 20/5 = 4

thus, x = 4
and, 4x = 16

Thus, the answer is (C) 16 boys and 4 girls

2) According to distributivity, a(b+c) = ab + ac

Thus, the answer is (C)
7 0
3 years ago
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Two triangles have altitudes of equal length. if the areas of these triangles have a ratio of 3:4 then the bases of the triangle
MatroZZZ [7]
Answer:
3/4
Area of the small triangle/Area of larger triangle=3/4

Area of the small triangle/Area of larger triangle=(1/2×base of small triangle×length)/(1/2×base of larger triangle×height)
3/4=(1/2×base of small triangle×height)/(1/2×base of larger triangle×height)
Since the length of the triangle are equal the base ratio of the two triangles is the same as area ratio.
5 0
4 years ago
How do I solve this problem?
Sedaia [141]

Answer:the value of x will be -4 and the value of y will be 40

Step-by-step explanation:-7x+12=-3x+8

3 0
3 years ago
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Please help solve this question
sineoko [7]
(-2x^3y^4z^0)^4

<span><span><span>(−2<span>x^<span><span>​3</span><span>​​^</span></span></span><span>y<span><span>​4</span><span>​​</span></span></span>×^1)</span><span><span>​4</span><span>​​
</span></span></span><span>
(-2x^3y^4)^4

(2x^3y^4)^4

2^4(x^3)^4(y^4)^4

16(x^3)^4(y^4)^4

16x^12(y^4)^4</span></span>
8 0
3 years ago
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Please help<br>are these functions or not?​
crimeas [40]

Answer:

1. Function

2. Not a function

3. Function

4. Not a function

Step-by-step explanation:

A function just means that for each input it outputs only 1 output. This output isn't necessarily unique. So for example if you're just given: f(2) = 3 and f(1) = 3, this is a function since each input only outputs 1 value, even though the output isn't unique, but if you're given: f(3) = 2, f(2) = 1, f(3) = 3. that's not a function since f(3) outputs both 2 and 3.

Anyways now that you hopefully understand this, let's look at each image.


Relation 1: (Function)

   So for each input (the domain) it's only pointing to one output (range), even if multiple input (the domain) are pointing to the same output (the range), it's still a function.

Relation 2: (Not a function)

   This is not a function, since if you look at the input 7 (the range), you'll see it outputs two things (range). It outputs -6 and -7. So this is not a function

Relation 3: (Function)

   This is a function since each x-value (input) has only one y-value (output). So it's a function

Relation 4: (Not a functio)

   This is not a function, since there are multiply coordinates with the same x-coordinate (input) and different y-coordinates (output). The x-coordinate 2 has the output b, y, and m, and since no value is given for these variables, it can be assumed they're different values, thus it's not a function.

5 0
2 years ago
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