The "standard" parabola with roots 0 and 2 is
All multiples of this parabola, i.e.
have the same roots. We can choose the factor such that the parabola passes through the desided point: if we plug 1, 5 for x, y we have
So, our claim is that the parabola
has roots 0 and 2 and vertex at (1, 5).
You can easily verify this: the roots are guaranteed by the fact that we can write the equation as
The vertex must be at x=1, because it's the midpoint of the roots. Moreover, if we evaluate the function at x=1 we have
as required.
Answer:
ture i gess
Step-by-step explanation:
Answer:
3
Step-by-step explanation:
1,2,3,4,5,6.
1,3,5
The relation between the legs and the hypotenuse of the right-angled triangle can be expressed using the Pythagorean theorem as follows:
We are given that a and b are the legs and we need to compute the hypotenuse. This means that all we need to do is substitute in the above formula.
<u>Question 7:</u>
a = 6 and b = 8
hypotenuse = units
<u>Question 8:</u>
a = 5 and b = 9
hypotenuse = units which is approximately 10.3 units
<u>Question 9:</u>
a = 4 and b = 10
hypotenuse = units which is approximately 10.8 units
<u>Question 10:</u>
a = 9 and b = 1
hypotenuse = units which is approximately 9.1 units
<u>Question 11:</u>
a = 7 and b = 3.5
hypotenuse = units which is approximately 7.8 units
<u>Question 12:</u>
a = 1.4 and b = 2.3
hypotenuse = units which is approximately 2.7 units
Hope this helps :)