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Nadya [2.5K]
4 years ago
9

What is area of a park that is 100 yards square

Mathematics
1 answer:
Savatey [412]4 years ago
8 0
Area=a^2
=100^2
=1000
hope that helps
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Trinity! Math skills needed here lol
Genrish500 [490]

Answer:

The slope of the line is 6

Step-by-step explanation:

The slope of the line is given by

m=(y2-y1)/(x2-x1)

m =(8-2)/(2-1)

   = 6/1

The slope of the line is 6

5 0
3 years ago
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A company is selling two different size medicine balls to a local colleges athletic department. The ratio of the ball diameters
dybincka [34]

Answer:

D. 220,781.25 cm3

Step-by-step explanation:

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3 years ago
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Find the length if each arc, round your answers to the nearest tenth.
klasskru [66]

Answer:

240

Step-by-step explanation:

in this circle you can fit in total 3 angles which a 120º

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6 0
3 years ago
find an equation of the tangent plane to the given parametric surface at the specified point. x = u v, y = 2u2, z = u − v; (2, 2
Alexxandr [17]

The surface is parameterized by

\vec s(u,v) = x(u, v) \, \vec\imath + y(u, v) \, \vec\jmath + z(u, v)) \, \vec k

and the normal to the surface is given by the cross product of the partial derivatives of \vec s :

\vec n = \dfrac{\partial \vec s}{\partial u} \times \dfrac{\partial \vec s}{\partial v}

It looks like you're given

\begin{cases}x(u, v) = u + v\\y(u, v) = 2u^2\\z(u, v) = u - v\end{cases}

Then the normal vector is

\vec n = \left(\vec\imath + 4u \, \vec\jmath + \vec k\right) \times \left(\vec \imath - \vec k\right) = -4u\,\vec\imath + 2 \,\vec\jmath - 4u\,\vec k

Now, the point (2, 2, 0) corresponds to u and v such that

\begin{cases}u + v = 2\\2u^2 = 2\\u - v = 0\end{cases}

and solving gives u = v = 1, so the normal vector at the point we care about is

\vec n = -4\,\vec\imath+2\,\vec\jmath-4\,\vec k

Then the equation of the tangent plane is

\left(-4\,\vec\imath + 2\,\vec\jmath - 4\,\vec k\right) \cdot \left((x-2)\,\vec\imath + (y-2)\,\vec\jmath +  (z-0)\,\vec k\right) = 0

-4(x-2) + 2(y-2) - 4z = 0

\boxed{2x - y + 2z = 2}

6 0
2 years ago
Please help! Geometry!
MrRa [10]

Answer:

\frac{2\pi}{ 3}  = 120 \: degrees

arc PR = 2\pi.r( \frac{120}{360} )

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=  \frac{16\pi}{3}

option D

5 0
3 years ago
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