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3 years ago

11

Please help. look at the picture.

1 answer:

ANEK [815]3 years ago

6 0

Answer:

33

Step-by-step explanation:

Line 1: 2

Line 2: 2 * 2 - 1 = 3

Line 3: 2 * 3 - 1 = 5

Line 4: 2 * 5 - 1 = 9

Line 5: 2 * 9 - 1 = 17

Line 6: 2 * 17 - 1 = 33

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Evaluate the expression 2n - 6 if n = 16.

V125BC [204]

Answer:

$26$

Step-by-step explanation:

$2n-6$

Given that:

$n=16$

To evaluate the expression, we must simply substitute the given value of $n$ , which is $16$ , for $n$ :

$2(16)-6$

Multiply:

$32-6$

Subtract:

$26$

-

To check your work, simply set the given expression equal to our solution, $26$ :

$2n-6=26$

Add $6$ to both sides of the equation:

$2n=32$

Divide both sides of the equation by the coefficient of $n$ , which is $2$ :

$n=16$

Since it matches the given value of $n$ , our solution is correct!

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2 years ago

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storchak [24]

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3 years ago

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Yee dealin with a dummy wats 3÷3/10

daser333 [38]

Answer:

0.1 I believe would be your answer

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3 years ago

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If there are approximately 1.8 million cars in Vancouver and if each car travels an average of 17,500 kilometres in a year, how

Goryan [66]

Rates are used to measure a quantity over another.

<em>The 1.8 million cars use </em> $1.85 \times 10^{10}$ <em> liters each year</em>

Given

$Cars = 1.8\ million$

$d = 17500km$ --- distance

$r = 40miles/gallon$

First, we calculate the number (n) of gallons used by each car

$r = \frac{d}{n}$

Solve for n

$n = \frac{d}{r}$

So, we have:

$n = \frac{17500km}{40miles/gallon}$

$n = \frac{17500km}{40miles}gallon$

Convert miles to kilometers

$n = \frac{17500km}{40km \times 1.60934}gallon$

$n = \frac{17500km}{64.3738km}gallon$

$n = 271.85\ gallon$

The number of gallons (N), used by all the cars is:

$N = n \times cars$

$N = 271.85 \times 1.8\ million$

$N = 489330000$

Convert to liters

$N = 489330000 \times 3.78541L$

$N = 1852314675.3L$

In scientific notation to 2 decimal places, we have:

$N = 1.85 \times 10^{10}L$

<em>Hence, the number of liters used is </em> $1.85 \times 10^{10}$ <em />

Read more about distance and rates at:

brainly.com/question/24659604

4 0

3 years ago

An environmental science teacher at a high school with a large population of students wanted to estimate the proportion of stude

AnnZ [28]

Answer:

60 students

Step-by-step explanation:

The confidence interval of a proportion is given by:

$p\pm z*\sqrt{\frac{p*(1-p)}{n} }$

Where 'p' is the proportion of students who responded 'yes', 'z' is the z-score for a 95% confidence interval (which is known to be 1.960), and 'n' is the number of students in the sample.

If the confidence interval is from 0.584 to 0.816, then:

$p=\frac{0.584+0.816}{2}=0.7 \\0.816-0.584=2*(1.96*\sqrt{\frac{p*(1-p)}{n}}) \\0.116=1.96*\sqrt{\frac{0.7*(1-0.7)}{n}}\\n=16.8966^2*(0.7*0.3)\\n=60\ students$

60 students were in the sample.

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3 years ago