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AlladinOne [14]

3 years ago

12

if Yvonne wanted to make 3 dresses that use 4 7/8 ad of fabric each, explain how she could use estimation to make sure she has e

nough fabric for all of them.

1 answer:

LuckyWell [14K]3 years ago

4 0

Using estimation you could round up the 4 7/8 to 5 and multiply by 5 so estimating 15 of fabric

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Manuel needs to make a total of 60 deliveries this week. So far he has completed 36 of them. What percentage of his total delive

Alenkasestr [34]

Answer:

60%

Step-by-step explanation:

It’s simple

He needs to do 60, he has done 36

Percentage = (36/60) * 100

= 60%

5 0

4 years ago

What is thesum of the two polynomials ? (-x^2+9)+(-3x^2-11x+4)

True [87]

-x^2 + 9 - 3x^2 - 11x + 4
-4x^2 - 11x + 13

3 0

3 years ago

What is the equation, in slope-intercept form, of the line parallel to y = 5x+2 that passes through the point (-2, 1)?

o-na [289]

Y=5x+11 using the point-slope formula and simplifying

4 0

3 years ago

I'd greatly appreciate the help-

dem82 [27]

Answer:

The 3rd option

Step-by-step explanation:

To prove that 2 triangles are similar, we need to prove that 2 pairs of their angle measurements are congruent.

This is because all triangles have 180 degrees, so if 2 pairs are congruent, the remaining angles will also be congruent

We know that m<D=m<E

We also know that m<DCA=m<ECB because they are vertical angles.

Vertical angles are always congruent.

Therefore, the triangles are similar.

The correct similarity statement would be 1, since <D corresponds with <E.

Now let's look at the 3rd Statement. To prove that two lines are similar, we would have to prove that their alternate interior angles are congruent.

A pair of alternate interior angles would be <D and B or or <E and <A

There is no way to prove this, since we do not know any of the angle or that measurements or if the triangles are isosceles triangles.

Hence, the correct choice would be 1 only.

7 0

3 years ago

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

PolarNik [594]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

= $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

$S_{{\bigtriangleup}ABC}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|$

= $=(\frac{1}{2})|-4-6 -8|= 9 units^2$

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

$S_{{\bigtriangleup}ACD'}$ = $(\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|$

$=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2}$ = 10.5 units²

Area of polygon = $S_{{\bigtriangleup}ABCD'}$ = $S_{{\bigtriangleup}ABC}$ + $S_{{\bigtriangleup}ACD'}$ = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

8 0

4 years ago