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3 years ago

I'd greatly appreciate the help-

Mathematics

1 answer:

dem82 [27]3 years ago

7 0

Answer:

The 3rd option

Step-by-step explanation:

To prove that 2 triangles are similar, we need to prove that 2 pairs of their angle measurements are congruent.

This is because all triangles have 180 degrees, so if 2 pairs are congruent, the remaining angles will also be congruent

We know that m<D=m<E

We also know that m<DCA=m<ECB because they are vertical angles.

Vertical angles are always congruent.

Therefore, the triangles are similar.

The correct similarity statement would be 1, since <D corresponds with <E.

Now let's look at the 3rd Statement. To prove that two lines are similar, we would have to prove that their alternate interior angles are congruent.

A pair of alternate interior angles would be <D and B or or <E and <A

There is no way to prove this, since we do not know any of the angle or that measurements or if the triangles are isosceles triangles.

Hence, the correct choice would be 1 only.

You might be interested in

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the n

Ivanshal [37]

Answer:

a) The probability that exactly 4 flights are on time is equal to 0.0313

b) The probability that at most 3 flights are on time is equal to 0.0293

c) The probability that at least 8 flights are on time is equal to 0.00586

Step-by-step explanation:

The question posted is incomplete. This is the complete question:

United Airlines' flights from Denver to Seattle are on time 50 % of the time. Suppose 9 flights are randomly selected, and the number on-time flights is recorded. Round answers to 3 significant figures.

a) The probability that exactly 4 flights are on time is =

b) The probability that at most 3 flights are on time is =

c)The probability that at least 8 flights are on time is =

<h2>Solution to the problem</h2>

a) Probability that exactly 4 flights are on time

Since there are two possible outcomes, being on time or not being on time, whose probabilities do not change, this is a binomial experiment.

The probability of success (being on time) is p = 0.5.

The probability of fail (note being on time) is q = 1 -p = 1 - 0.5 = 0.5.

You need to find the probability of exactly 4 success on 9 trials: X = 4, n = 9.

The general equation to find the probability of x success in n trials is:

$P(X=x)=_nC_x\cdot p^x\cdot (1-p)^{(n-x)}$

Where $_nC_x$ is the number of different combinations of x success in n trials.

$_nC_x=\frac{x!}{n!(n-x)!}$

Hence,

$P(X=4)=_9C_4\cdot (0.5)^4\cdot (0.5)^{5}$

$_9C_4=\frac{4!}{9!(9-4)!}=126$

$P(X=4)=126\cdot (0.5)^4\cdot (0.5)^{5}=0.03125$

b) Probability that at most 3 flights are on time

The probability that at most 3 flights are on time is equal to the probabiity that exactly 0 or exactly 1 or exactly 2 or exactly 3 are on time:

$P(X\leq 3)=P(X=0)+P(X=1)+P(X=2)+P(X=3)$

$P(X=0)=(0.5)^9=0.00195313$ . . . (the probability that all are not on time)

$P(X=1)=_9C_1(0.5)^1(0.5)^8=9(0.5)^1(0.5)^8=0.00390625$

$P(X=2)=_9C_2(0.5)^2(0.5)^7=36(0.5)^2(0.5)^7=0.0078125$

$P(X=3)= _9C_3(0.5)^3(0.5)^6=84(0.5)^3(0.5)^6=0.015625$

$P(X\leq 3)=0.00195313+0.00390625+0.0078125+0.015625=0.02929688\\\\ P(X\leq 3) \approx 0.0293$

c) Probability that at least 8 flights are on time 

That at least 8 flights are on time is the same that at most 1 is not on time.

That is, 1 or 0 flights are not on time.

Then, it is easier to change the successful event to not being on time, so I will change the name of the variable to Y.

$P(Y=0)=_0C_9(0.5)^0(0.5)^9=0.00195313\\ \\ P(Y=1)=_1C_9(0.5)^1(0.5)^8=0.0039065\\ \\ P(Y=0)+P(Y=1)=0.00585938\approx 0.00586$

6 0

4 years ago

A triangle has a side length of 6 centimeters , 8 centimeters, and 12 centimeters the triangle is to be enlarged by a scale fact

marshall27 [118]

Answer:

30 centimeters

Step-by-step explanation:

12 times 2.5 = 30

8 0

3 years ago

Read 2 more answers

What is the average rate of change of the function f(x)=20(14)xf(x)=20(14)x from x = 1 to x = 2? Enter your answer, as a decimal

Advocard [28]

The average rate of a function f(x) over an interval x = a and x = b is given by:

$Average \ Rate \ of \ Change= \frac{f(b)-f(a)}{b-a}$

Given the function

$f(x)=20(14)^x$

The average rate of change from x = 1 to x = 2 is given by:

$\frac{f(2)-f(1)}{2-1} = \frac{20(14)^2-20(14)^1}{1} \\ \\ =20(196-14)=20(182)=3,640$