All categories

3 years ago

Solve the problem 5x+(x+6)+3x

Mathematics

1 answer:

nikdorinn [45]3 years ago

4 0

what how am I solving do I simplify

You might be interested in

I need the solution

Vikki [24]

Answer:

=3/4

Step-by-step explanation:

3 (c+d) 2c-2d

-------------- * -------------

(c-d) 8c+8d

Factor the right had term. The numerator can factor out a 2 and the denominator can factor out an 8.

3 (c+d) 2(c-d)

-------------- * -------------

(c-d) 8(c+d)

We can cancel the (c+d) in the numerator the left and the denominator on the right. We can cancel the (c-d) in the numerator on the right and the denominator on the left

3 2

-------------- * -------------

1 8

We can divide the fraction on the right by 2 on the top and bottom.

3 1

-------------- * -------------

1 4

=3/4

4 0

4 years ago

Please help me out!!!!!!!!!!!!!

Olenka [21]

The equation given means it wants you to solve in the format y=mx+b, for a line. You can also know that by comparing the difference between each y-coordinates.

m is the slope. b is the y intercept (where x is zero, which is on the table).

The answer is y=6x-2

6 0

3 years ago

How to i figure this out ?

fiasKO [112]

Tip - for finding the surface area of a triangle put two of them together so it forms a square find the area of that square and divide it by 2

5 0

4 years ago

Describe the graph y=|x-2|+4

ICE Princess25 [194]

Answer: D) a V shaped graph with vertex at(2,4) which opens up

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A Niffler is a magical creature who loves to collect shiny objects and store them in their pouch, much like a kangaroo. The amou

Fudgin [204]

Answer:

Probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

Step-by-step explanation:

We are given that the amount a Niffler can hold in their pouch is approximately normally distributed with a mean of 25 pounds of shiny objects and a standard deviation of 6.8 pounds.

Let X = amount a Niffler can hold in their pouch

So, X ~ Normal( $\mu=25,\sigma^{2} =6.8^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 25 pounds

$\sigma$ = standard deviation = 6.8 pounds

Now, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is given by = P(X > 32 pounds)

P(X > 32 pounds) = P( $\frac{X-\mu}{\sigma}$ > $\frac{32-25}{6.8}$ ) = P(Z > 1.03) = 1 - P(Z $\leq$ 1.03)

= 1 - 0.8485 = 0.1515

The above probability is calculated by looking at the value of x = 1.03 in the z table which has an area of 0.8485.

Hence, the probability that a Niffler can hold more than 32 pounds of shiny objects in their pouch is 0.1515.

4 0

3 years ago