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3 years ago

10

19 is 50% of what number?

2 answers:

Arlecino [84]3 years ago

7 0

Answer:

38

Step-by-step explanation:

the easy way to figure out what a number is 50% of

19 x 2

38

Sonja [21]3 years ago

5 0

Answer:

38

Step-by-step explanation:

<u>Step 1: Change words into an expression</u>

19 is %50 of what number

19 * 2

38

Answer: 38

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A package of 24 pencils costs 2.88$. at this rate how much would 30 pencils cost?

ASHA 777 [7]

24➗2.88=0.8 30➗0.8 = 3.75 So the answer is 3.75

6 0

3 years ago

Multiply the following radicals (do NOT simplify)<br> 2/4 x 416

Tpy6a [65]

Answer:

208

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.

o-na [289]

Answer: $\text{Length of AG=}\frac{2\sqrt{63}}{3}$

Explanation:

Please follow the diagram in attachment.

As we know median from vertex C to hypotenuse is CM

$\therefore CM=\frac{1}{2}AB$

We are given length of CG=4

Median divide by centroid 2:1

CG:GM=2:1

Where, CG=4

$\therefore GM=2$ ft

Length of CM=4+2= 6 ft

$\therefore CM=\frac{1}{2}AB\Rightarrow AB=12$

In $\triangle ABC, \angle C=90^0$

Using trigonometry ratio identities

$AC=AB\sin 30^0\Rightarrow AC=6$ ft

$BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3}$ ft

$CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3}$ ft

In $\triangle CAN, \angle C=90^0$

Using pythagoreous theorem

$AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}$

Length of AG=2/3 AN

$\text{Length of AG=}\frac{2\sqrt{63}}{3}$ ft

5 0

3 years ago

if each side of a square classroom is 25 feet then what is the perimeter of the room? what is the area of the floor of the room?

Svetllana [295]

Answer:

P = 100

Area = 625

Step-by-step explanation:

Area = s^2

sqrt(area) = sqrt(s^2)

area = 25*25

sqrt(25*25) = sqrt(s^2)

s = 25

P = 4*s

P = 4 * 25

P = 100

Area = s^2

s = 25

Area = 25^2

Area = 625

4 0

3 years ago

(hg^(-3))/(w^(-4) k^0 )

Svetlanka [38]

One may note you never quite asked anything, now, assuming simplification,

$\bf ~~~~~~~~~~~~\textit{negative exponents}\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
\cfrac{hg^{-3}}{w^{-4}k^0}\implies \cfrac{hw^4}{g^3(1)}\implies \cfrac{hw^4}{g^3}$

4 0

3 years ago