All categories

3 years ago

Need help ASAP please

Mathematics

2 answers:

ratelena [41]3 years ago

8 0

Answer:

I think its 22%

Step-by-step explanation:

fredd [130]3 years ago

5 0

Answer:

22%

Step-by-step explanation:

x/100 * 160=35

160x=3500

21.875

hence to the nearest percent: 22%

You might be interested in

At 2 PM, a thermometer reading 80°F is taken outside where the air temperature is 20°F. At 2:03 PM, the temperature reading yiel

Alexeev081 [22]

Use Law of Cooling:
$T(t) = (T_0 - T_A)e^{-kt} +T_A$
T0 = initial temperature, TA = ambient or final temperature

First solve for k using given info, T(3) = 42
$42 = (80-20)e^{-3k} +20 \\ \\ e^{-3k} = \frac{22}{60}=\frac{11}{30} \\ \\ k = -\frac{1}{3} ln (\frac{11}{30})$

Substituting k back into cooling equation gives:
$T(t) = 60(\frac{11}{30})^{t/3} + 20$

At some time "t", it is brought back inside at temperature "x".
We know that temperature goes back up to 71 at 2:10 so the time it is inside is 10-t, where t is time that it had been outside.
The new cooling equation for when its back inside is:
$T(t) = (x-80)(\frac{11}{30})^{t/3} + 80 \\ \\ 71 = (x-80)(\frac{11}{30})^{\frac{10-t}{3}} + 80$
Solve for x:
$x = -9(\frac{11}{30})^{\frac{t-10}{3}} + 80$
Sub back into original cooling equation, x = T(t)
$-9(\frac{11}{30})^{\frac{t-10}{3}} + 80 = 60 (\frac{11}{30})^{t/3} +20$
Solve for t:
$60 (\frac{11}{30})^{t/3} +9(\frac{11}{30})^{\frac{-10}{3}}(\frac{11}{30})^{t/3} = 60 \\ \\ (\frac{11}{30})^{t/3} = \frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}} \\ \\ \\ t = 3(\frac{ln(\frac{60}{60+9(\frac{11}{30})^{\frac{-10}{3}}})}{ln (\frac{11}{30})}) \\ \\ \\ t = 4.959$

This means the exact time it was brought indoors was about 2.5 seconds before 2:05 PM

8 0

3 years ago

Simplify -1/6(6x-12y)

harkovskaia [24]

Factor the expression:
-1/6*6(x-2y)
Divide by 6
-1(x-2y)
Then times by -1
-x+2y
Is your answer
Hope this helps

3 0

3 years ago

Read 2 more answers

Fraction that is equivalent to but different from 4/13

dem82 [27]

Answer:

8/26

Step-by-step explanation:

All you have to do is multiply the numerator and denominator with the same number. For example, I did 2. 4x2=8, and 2x13=26.

4 0

3 years ago

What is the critical value at the 0.05 level of significance for a goodness-of-fit test if there are six categories?

9966 [12]

Answer:

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

Step-by-step explanation:

For n=6 the degrees of freedom will be n-1 = 5 .

The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )

The critical region depends on ∝ and the alternative hypothesis

a) When Ha is σ²≠σ² the critical region is

χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test

( χ² < 0.83) and ( χ² > 0.83)

b) When Ha is σ²> σ² the critical region falls in the right tail and its value is

χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}

c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value

χ²(1-∝)(n-1) One tailed test (1.145)

6 0

3 years ago

Read 2 more answers

What does -15x + 39 equal

Anna [14]

Answer: (‑(15*x))+39

Step-by-step explanation:

5 0

2 years ago