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3 years ago

12

Find the length of AB if AC=18 and BC=7

1 answer:

kotegsom [21]3 years ago

3 0

Answer:

25

Step-by-step explanation:

Step 1:

AC + BC = AB Equation

Step 2:

18 + 7 = AB Substitute

Answer:

25 Add

Hope This Helps :)

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Point B is in between A and C in a segment. AB= 22 and BC=30 Find AC

dolphi86 [110]

Answer:

AC = 52

Step-by-step explanation:

Add the segment lengths together.

AB + BC = AC

22 + 30 = 52

4 0

3 years ago

Find each measure plz help

Rashid [163]

Answer:

m∠QRS = 52°

Step-by-step explanation:

From the given figure,

In right triangles ΔRQT and ΔRST,

QT = TS = 7.5 units [Given]

RT ≅ RT [Reflexive property]

ΔRQT ≅ ΔRST [By HL theorem of congruence]

Therefore, m(∠QRT) = m(∠SRT) = 26° [CPCTC]

m(∠QRS) = 2m(∠QRT)

= 2×(26°)

= 52°

4 0

3 years ago

What are the coordinates of the orthocenter of △JKL with vertices at J(−4, −1) , K(−4, 8) , and L(2, 8) ?

kompoz [17]

Answer:

K(-4,8) is the ortho center.

Step-by-step explanation:

In a right angled triangle, The vertex of the right angle is the ortho center.

Here we are given

J(-4,-1), K(-4,8) & L(2,8)

Using distance formula we get

$JK^{2}= (-4+4)^{2}+ (8+1)^{2}=0+81=81$

$KL^{2}= (-4-2)^{2}+ (8+-8)^{2}=36+0=36$

$JL^{2}= (-4-2)^{2}+ (8+1)^{2}=36+81=117$

So we can say that

$JK^2 + KL^2=JL^2$

By converse of pythagorean theorem we get

Hence the Vertex of the right angle is K(-4,8)

K(-4,8) is the ortho center.

7 0

3 years ago

5. 6(2+ y)=3(3- y)<br> Help

Maurinko [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

Help please need answer

gavmur [86]

I think its 2 (not sure though just a guess)

4 0

3 years ago