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VikaD [51]
3 years ago
10

Do You Know How?

Mathematics
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

3. 4,715 (estimate: 5,000)

4. 3,672 (estimate: 3,300)

5. 18,040 (estimate: 16,000)

6. 9,060 (estimate: 9,000)

Explanation:

It is reasonable if your answer is somewhat close to the estimate.

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Which of the following best describes how the y values are changing over each interval?
ziro4ka [17]

Answer:

y=ax+b

a=-0.6020457867

b=-2.256697516   <------- There is your value for b, which is the answer to the problem.

You can use these values for a and b to generate an equation in slope-intercept form, which you can then enter under Y= and view the graph.

Step-by-step explanation:

6 0
2 years ago
Uninhibited growth can be modeled by exponential functions other than​ A(t) ​=Upper A 0 e Superscript kt. For ​ example, if an i
laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than A(t)=A_{0}e^{kt}. for example, if an initial population P₀ requires n units of time to triple, then the function P(t)=P_{0}(3)^{\frac{t}{n} } models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form P(t)=P_{0}(3)^{\frac{t}{n} } that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form A(t)=A_{0}e^{kt}.

Answer: a) P(t)=50(3)^{\frac{t}{30} }

              b) P(t) = 280 insects

              c) t = 74 days

             d) A(t)=50e^{0.037t}

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

P(t)=50(3)^{\frac{t}{30} }

b) In t = 47 days:

P(t)=50(3)^{\frac{t}{30} }

P(47)=50(3)^{\frac{47}{30} }

P(47)=50(3)^{1.567}

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

750=50(3)^{\frac{t}{30} }

\frac{750}{50}=(3)^{\frac{t}{30} }

(3)^{\frac{t}{n} }=15

Using the property <u>Power</u> <u>Rule</u> of logarithm:

log(3)^{\frac{t}{30} }=log15

\frac{t}{30}log(3)=log15

t=\frac{log15}{log3} .30

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

A(t)=A_{0}e^{kt}

3A_{0}=A_{0}e^{30k}

3=e^{30k}

Use Power Rule again:

ln3=ln(e^{30k})

ln3=30k

k=\frac{ln3}{30}

k = 0.037

Equation for exponential growth will be:

A(t)=50e^{0.037t}

3 0
3 years ago
Help pls!!!!!!!!!!!!!!
Sholpan [36]

Answer:

46°

Step-by-step explanation:

tan Ф = 21/20

Ф = tan-1 (21/20)

= 46°

8 0
3 years ago
The stem-and-leaf plot lists the number of different ingredients found in different industrial cleaners.
Neporo4naja [7]
<span>A Stem and Leaf Plot is a special table where each data value is split into a "stem" (the first digit or digits) and a "leaf" (usually the last digit).

</span>Since the key says 4|0= 40 the answer to your question is 12. Twelve cleaners have more than 80 ingredients.

Hope this helps :)
5 0
3 years ago
Read 2 more answers
Which of the following is the solution set of x2 + 8x + 12 = 0?<br> (-2.-6<br> 2.6
algol [13]

To solve this polynomial equation, we first factor the left side.

To factor x² + 8x + 12 = 0, look for factors of 12 that add to 8.

These factors are 6 and 2 so we have (x + 6)(x + 2) = 0.

So either x + 6 = 0 or x + 2 = 0 and solving for

x in each equation, our answer is {-6, -2}.

6 0
3 years ago
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