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3 years ago

Do You Know How?

Mathematics

1 answer:

Gre4nikov [31]3 years ago

5 0

Answer:

3. 4,715 (estimate: 5,000)

4. 3,672 (estimate: 3,300)

5. 18,040 (estimate: 16,000)

6. 9,060 (estimate: 9,000)

Explanation:

It is reasonable if your answer is somewhat close to the estimate.

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Which of the following best describes how the y values are changing over each interval?

ziro4ka [17]

Answer:

y=ax+b

a=-0.6020457867

b=-2.256697516 <------- There is your value for b, which is the answer to the problem.

You can use these values for a and b to generate an equation in slope-intercept form, which you can then enter under Y= and view the graph.

Step-by-step explanation:

6 0

2 years ago

Uninhibited growth can be modeled by exponential functions other than A(t) =Upper A 0 e Superscript kt. For example, if an i

laila [671]

The question is incomplete. Here is the complete question.

Uninhibited growth can be modeled by exponential functions other than $A(t)=A_{0}e^{kt}$ . for example, if an initial population P₀ requires n units of time to triple, then the function $P(t)=P_{0}(3)^{\frac{t}{n} }$ models the size of the population at time t. An insect population grows exponentially. Complete the parts a through d below.

a) If the population triples in 30 days, and 50 insects are present initially, write an exponential function of the form $P(t)=P_{0}(3)^{\frac{t}{n} }$ that models the population.

b) What will the population be in 47 days?

c) When wil the population reach 750?

d) Express the model from part (a) in the form $A(t)=A_{0}e^{kt}$ .

Answer: a) $P(t)=50(3)^{\frac{t}{30} }$

b) P(t) = 280 insects

c) t = 74 days

d) $A(t)=50e^{0.037t}$

Step-by-step explanation:

a) n is time necessary to triple the population of insects, i.e., n = 30 and P₀ = 50. So, Exponential equation for growth is

$P(t)=50(3)^{\frac{t}{30} }$

b) In t = 47 days:

$P(t)=50(3)^{\frac{t}{30} }$

$P(47)=50(3)^{\frac{47}{30} }$

$P(47)=50(3)^{1.567}$

P(47) = 280

In 47 days, population of insects will be 280

c) P(t) = 750

$750=50(3)^{\frac{t}{30} }$

$\frac{750}{50}=(3)^{\frac{t}{30} }$

$(3)^{\frac{t}{n} }=15$

Using the property Power Rule of logarithm:

$log(3)^{\frac{t}{30} }=log15$

$\frac{t}{30}log(3)=log15$

$t=\frac{log15}{log3} .30$

t = 74

To reach a population of 750 insects, it will take 74 days

d) To express the population growth into the described form, determine the constant k, using the following:

A(t) = 3A₀ and t = 30

$A(t)=A_{0}e^{kt}$

$3A_{0}=A_{0}e^{30k}$

$3=e^{30k}$

Use Power Rule again:

$ln3=ln(e^{30k})$

$ln3=30k$

$k=\frac{ln3}{30}$

k = 0.037

Equation for exponential growth will be:

$A(t)=50e^{0.037t}$

3 0

3 years ago

Help pls!!!!!!!!!!!!!!

Sholpan [36]

Answer:

46°

Step-by-step explanation:

tan Ф = 21/20

Ф = tan-1 (21/20)

= 46°

8 0

3 years ago

The stem-and-leaf plot lists the number of different ingredients found in different industrial cleaners.

Neporo4naja [7]

A Stem and Leaf Plot is a special table where each data value is split into a "stem" (the first digit or digits) and a "leaf" (usually the last digit).

Since the key says 4|0= 40 the answer to your question is 12. Twelve cleaners have more than 80 ingredients.

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Which of the following is the solution set of x2 + 8x + 12 = 0? (-2.-6 2.6

algol [13]

To solve this polynomial equation, we first factor the left side.

To factor x² + 8x + 12 = 0, look for factors of 12 that add to 8.

These factors are 6 and 2 so we have (x + 6)(x + 2) = 0.

So either x + 6 = 0 or x + 2 = 0 and solving for

x in each equation, our answer is {-6, -2}.

6 0

3 years ago