Answer:
angle M and N are right angles
we can draw a line joining M and N
so we’d have a triangle MNC AND KMN
both MNC AND KMN BECOME ISOSCELES TRIANGLES
so since we have 55 degrees for angle MKN. We have to find the other 2
180-55=125
now divide by 2 to get 62.5 for each of the remaining sides of triangle KMN
now to find the sides of triangle MNC
90-62.5= 27.5
27.5*2= 55
180-55=125=angle C
(sorry, it’s complex)
Answer:
Step-by-step explanation:
First, rewrite the given equation in the form of y=mx+c.
m is the gradient while c is the y-intercept.
3x-5y=8
5y= 3x -8
Thus, the gradient of the given equation is ⅗.
The product of the gradients of perpendicular lines is -1.
(gradient of line)(⅗) = -1
gradient of line= -1 ÷⅗
gradient of line= 
To find the value of c, substitute a coordinate.
When x=3, y=7,
7= -5 +c
c= 7+5
c= 12
Hence, the equation of the line is .
Answer:
9
Step-by-step explanation:
x didn't change in value, y changed by 9
the distance between the two points is 9
<h2>JK = 18m</h2><h2>_______________</h2>
<u>Step-by-step explanation:</u>
ΔJLK = ΔNLM ( <em>v</em><em>e</em><em>r</em><em>t</em><em>i</em><em>c</em><em>a</em><em>l</em><em>l</em><em>y</em><em> </em><em>o</em><em>p</em><em>p</em><em>o</em><em>s</em><em>i</em><em>t</em><em>e</em><em> </em>Δ)
ΔJKL = ΔNML ( <em>e</em><em>a</em><em>c</em><em>h</em><em> </em><em>9</em><em>0</em><em>°</em><em> </em><em>)</em>
so,
triangle JKL = triangle NML (<em>b</em><em>y</em><em> </em><em>A</em><em>A</em><em> </em><em>s</em><em>i</em><em>m</em><em>i</em><em>l</em><em>a</em><em>r</em><em>i</em><em>t</em><em>y</em><em>)</em>
JK / KL = NM / ML
JK / 21m = 42m / 49m
JK = 42 × 21 ÷ 49
JK = 18m
<h2>_______________</h2><h2>FOLLOW ME</h2>
Answer:
x
=
y
=
A
E
=
2
x
=
E
C
=
y
+
4
=
D
E
=
x
=
E
B
=
2
y
−
1
A
C
=
B
D
=
E
=
Step-by-step explanation:
