What is the width of this shape
1 answer:
We see that the area is 159 3/8 and the length is 18 3/4.
Because the area is the length*width, to find the width, we must divide the area by the length.
Think of it this way:
Divide l on both sides:
And w is what we're looking for.
So, divide 159 3/8 by 18 3/4.
You should get that the width is 8.5 feet :)
Because the area is the length*width, to find the width, we must divide the area by the length.
Think of it this way:
Divide l on both sides:
And w is what we're looking for.
So, divide 159 3/8 by 18 3/4.
You should get that the width is 8.5 feet :)
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Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, is the point on the plane and
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .