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3 years ago

What is the width of this shape

Mathematics

1 answer:

77julia77 [94]3 years ago

7 0

We see that the area is 159 3/8 and the length is 18 3/4.

Because the area is the length*width, to find the width, we must divide the area by the length.

Think of it this way:
$A = l*w$

Divide l on both sides:
$\frac{A}{l} = w$

And w is what we're looking for.
So, divide 159 3/8 by 18 3/4.

You should get that the width is 8.5 feet :)

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PLEASE HELP 25PTS!! Select the correct answer from each drop-down menu.

lions [1.4K]

Answer:

The quality control facility operates for 10 hours each day.

Step-by-step explanation:

The given function models the number of cars that are put through a quality control test each hour at a car production factory.

The given function is

$c(t)= -t^2+8t+20$

We need to find the number of hours does the quality control facility operate each day.

Rewrite the given function it factored form.

$c(t)= -t^2+(10t-2t)+20$

$c(t)= (-t^2+10t)+(-2t+20)$

Taking out the common factors from each parenthesis.

$c(t)= -t(t-10)-2(t-10)$

$c(t)= (t-10)(-t-2)$

$c(t)=-(t-10)(t+2)$

The factored form of given function is c(t)=-(t-10)(t+2).

Equate the function equal to 0 to find the x-intercept.

$0=-(t-10)(t+2)$

$t-10=0\Rightarrow t=10$

$t+2=0\Rightarrow t=-2$

Number of hours cannot be negative. So from t=0 to t=10 quality control facility operate the cars.

Therefore the quality control facility operates for 10 hours each day.

7 0

3 years ago

Determine the value of the rest of the angles

Inessa [10]

Answer:

2, 5, 6 are all 154

1, 3, 4, and 7 are all 26

4 0

3 years ago

O is the centre of the circle. AB is a diameter.

viktelen [127]

Answer:

The value of a is 63° and the value of b is 27°

Step-by-step explanation:

In the given figure

∵ OA, OB, and OC are radii of the circle O

→ The radii of a circle are equal

∴ OA = OB = OC

In Δ AOC

∵ OA = OC

∴ Δ AOC is an isosceles triangle

→ Base angles of the isosceles triangle are equal

∵ ∠OAC and ∠OCA are the base angles of the triangle

∴ m∠OAC = m∠OCA

∵ m∠OAC = a°

∴ m∠OCA = a°

→ The sum of angles in any triangle is 180°

∵ a° + a° + m∠AOC = 180°

∵ m∠AOC = 54°

∴ a° + a° + 54 = 180°

→ Add the like terms

∴ 2a° + 54 = 180°

→ Subtract 54 from both sides

∴ 2a° = 126°

→ Divide both sides by 2

∵ m∠OAC = m∠OCA = 126 ÷ 2

∴ a° = 63

∴ The value of a is 63°

In ΔBOC

∵ OB = OC

∴ Δ BOC is an isosceles triangle

→ Base angles of the isosceles triangle are equal

∵ ∠OBC and ∠OCB are the base angles of the triangle

∴ m∠OBC = m∠OCB

∵ m∠OBC = b°

∴ m∠OCB = b°

∵ ∠AOC is an exterior angle of ΔBOC at the vertex O

→ The measure of the exterior angle equals the sum of the measure

of the opposite interior angles to this vertex

∵ ∠OBC and ∠OCB are the opposite interior angle of ∠AOC

∴ m∠OBC + m∠OCB = m∠AOC

→ Substitute their measures

∵ b° + b° = 54°

→ Add the like terms

∴ 2b° = 54

→ Divide both sides by 2

∴ b° = 27

∴ The value of b is 27°

3 0

2 years ago

Robert ran 3 1/3 mph for 3/4 of an hour. How far did he run?

matrenka [14]

Answer:

2 ½ miles

Explanation:

mph = miles per hour, which means that if robert had run for the full 1 hour, he would have run 3 ⅓ miles.

however, since he only ran for ¾ of an hour, which is equal to 0.75, we can multiply the 3 ⅓ miles by 0.75 to get 2.5 or 2 ½ miles.

i hope this helps! :D

7 0

3 years ago

Simon can see two lights, light A and light B.

xz_007 [3.2K]

Answer:

2 Times

Step-by-step explanation:

Simon can see two lights A and B

Light A flashes every 15 seconds.
Light B flashes every 18 seconds.

First, we determine the next time both lights will flash together.

This is done by finding the Least Common Multiple of 15 and 18.

15=3X5

18= $2X3^2$

LCM of 15 and 18= $2X3^2X5=90$

This means that lights A and B will first flash together after 90 seconds.

Now, 240/90= $2.\overline{6}$ seconds

Therefore, the number of times more both light will flash together in the next 4 Minutes= 2 Times

3 0

3 years ago