Answer:
y = 4x + 12 will be the other equation.
Step-by-step explanation:
Data given in the tables show a linear relation (has a common data).
To get the linear relation, we will choose the two points from table (1) .
Let the points are (1, 16) and (2, 20).
Slope of the line 'm' = 
m = 
m = 
m = 4
Equation of the line passing through (1, 16) having slope = 4
y - 16 = 4(x - 1)
y = 4(x - 1) + 16
y = 4x - 4 + 16
y = 4x + 12
Now we take second set of data,
We choose two points (1, 6) and (2, 12).
Slope 'm' = 
m = 
m = 6
Equation of the line passing through (1, 6) having slope = 6
y - 6 = 6(x - 1)
y = 6x - 6 + 6
y = 6x
Therefore, other equation of the system of equations will be,
y = 4x + 12
The answer is 4 because you round down due to the .2 not being greater than 5
Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3