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kompoz [17]
3 years ago
8

2/3a - 2 =1/3 Find the answer for a. Show all work please

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0
2/3a - 2= 1/3
add 2 to both sides
2/3a= 2 1/3
change mixed fraction to improper
2/3a= 7/3
divide both sides by 2/3
a= 7/3 ÷ 2/3
to divide fraction, multiply by reciprocal (inverse)
a= 7/3 * 3/2
a= (7*3)/(3*2)
a= 21/6
reduce by 3
a= 7/2 OR 3 1/2

ANSWER: 7/2 OR 3 1/2

Hope this helps! :)
blondinia [14]3 years ago
4 0
2/3a - 2 = 1/3
2/3a = 2 + 1/3
2/3a = 7/3
a = (7/3) / (2/3)
a = (7/3) * (3/2)
a = 21/6
a = 7/2 ---- that is the answer

Hope this helps!

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Lyrx [107]
Multiple both ratios by a least common denominator 
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6 0
3 years ago
Please help i have no clue
kozerog [31]

Answer:

Step-by-step explanation:

Question (1)

x² + 10x + 12

= x² + 2(5x) + 5² - 5² + 12

= [x² + 2(5x) + 5²] - 5² + 12

= (x + 5)² - 25 + 12 [Since, a² + 2ab + b² = (a + b)²]

= (x + 5)² - 13

Question (2)

y² - 6y - 15

= y² - 2(3y) - 15

= y² - 2(3y) + 3² - 3² - 15

= [y² - 2(3y) + 3²] - 3² - 15 [Since, a² - 2ab + b² = (a - b)²]

= (y - 3)² - 3²- 15

= (y - 3)² - 9 - 15

= (y - 3)² - 24

6 0
3 years ago
Which best explains whether a triangle with side lengths 5 cm, 13 cm, and 12 cm is a right triangle? The triangle is a right tri
stira [4]

Answer:

The Triangle Is A Right Triangle Because 5^2 + 12^2 = 13^2.

Step-by-step explanation:

5^2 = 25. 12^2 = 144. With the Pythagorean theorem, (a^2 + b^2 = c^2), 5 is a, 12 is b, and 13 is c.

25 + 144 = 169.

13 ^ 2 = 169.

Since a^2 + b^2 = c^2 is true, the triangle is a right triangle.

3 0
3 years ago
Read 2 more answers
At Mario's Pizza, a large pizza has a diameter of 18 inches. What is the area of two pizzas?
irinina [24]
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Plug in the values.

We will use 3.14 for \pi.

We need the radius. So half the diameter to get the radius.

18 / 2 = 9

Area = 3.14 * 9^2
Area = 3.14 * 81
Area = <span>254.34
</span>
Then multiply 2 to get the double the area.

254.34 * 2 = <span>508.68
</span>
So, the answer to this question is <span>D. 508.68 in. 2.</span>
4 0
3 years ago
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