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Usimov [2.4K]
3 years ago
9

In an average month, Jaden sends 200 texts and talks for 100 minutes. Give the cost for plan A and for plan B. Then tell which p

lan will cost Jaden the least amount of
money.
Plan A
Jaden has a prepaid phone plan (Plan A) that charges 15 cents for each text sent and 10 cents per minute for calls.
Plan B
Jaden discovers another prepaid phone plan (Plan B) that charges a flat fee of $15 per month, then $.05 per text sent or minute used.
Mathematics
1 answer:
amid [387]3 years ago
8 0

Answer:

Plan B

Step-by-step explanation:

Let's calculate the amount required for each plan

<h3>Plan A</h3>
  • 0.15*200 + 0.10*100 = $40
<h3>Plan B</h3>
  • 15 + 200*0.05 + 100*0.05 =  $30

As we see Plan B costs less

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URGENT!
klio [65]
1 dozen = 12........so 12 dozen eggs is (12 * 12) = 144 eggs

she sold 5/6 of the eggs.....so she sold : 5/6 * 144 = 720/6 = 120 eggs
she gave her friends (144 - 120) = 24 eggs

(a) 12x = 120.....with x being the number of dozens of eggs
        x = 120/12
        x = 10 <== she gave away 10 dozen eggs

(b) she sold a dozen for 4.50....
     4.50x = E .......x = the number of dozens of eggs sold and E = total             earned. She sold 10 dozen...so sub in 10 for x
     4.50(10) = E
    45 = E <=== she earned $ 45 from the eggs she sold
     
7 0
4 years ago
Read 2 more answers
Which of the following should not be capitalized?
Nataly_w [17]
Foreign words, because they are normal words you use to speak on like a daily basis. A, C, and D are events which need to be capitalized
5 0
2 years ago
Read 2 more answers
A population of rabbits is described by the function R(t) = 100(2t/5), where t is measured in months and R is measured in rabbit
Savatey [412]

Answer and Step-by-step explanation: The graph is shown in the attachment.

a. ΔR on [1,2] is mathematically expressed as:

ΔR = R(2) - R(1)

which means difference of population of rabbits after 2 months and after 1 month.

R(1) = 100(\frac{2}{5}.1 )

R(1) = 100(\frac{2}{5} )

R(2) = 100(\frac{2}{5}.2 )

R(2) = 100(\frac{4}{5} )

\Delta R = 100(\frac{4}{5} )-100(\frac{2}{5} )

\Delta R = 100[\frac{4}{5} - \frac{2}{5} ]

\Delta R= 40

Difference of rabbits between first and second months is 40.

b. R(0) = 100(\frac{2}{5} .0)

R(0) = 0

Initially, there no rabbits in the population.

c. R(10) = 100(\frac{2}{5}.10 )

R(10) = 400

In 10 months, there will be 400 rabbits.

d. R(t) = 500

500=100(\frac{2}{5}.t )

\frac{500}{100}=\frac{2}{5}.t

t = \frac{500.5}{100.2}

t = 12.5

In 12 and half months, population of rabbits will be 500.

3 0
3 years ago
I cant ever find this answer everywhere i look!!!!!! WHATS 1+1
Fynjy0 [20]
2 is the answer cause 1+1=2 I don’t know any other way to explain
6 0
3 years ago
A geometric sequence has an initial value of 2 and a common ratio of 3. Which formula would be more practical to use if you were
Makovka662 [10]

Answer:

19th term = ar^18

19th term = 774,840,978

Step-by-step explanation:

First term, a = 2

Common ratio, r = 3

nth term of a geometric sequence = ar^(n-1)

19th term = ar^(19-1)

19th term = ar^18

= 2 × 3^18

= 2 × 387,420,489

= 774,840,978

19th term = 774,840,978

8 0
3 years ago
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