Answer:
Two Endpoints
Step-by-step explanation:
That 10 is the diameter of the circle.
First let's find the area of the square.
A = s^2
Where 's' is the side.
A = 10^2
A = 100
Now let's find the area of the circle.
The '10' is also the diameter of the circle.
A = pi * r^2
A = 3.14 * 5^2
A = 3.14 * 25
A = 78.5
Now subtract this from the area of the square.
100 - 78.5 = 21.5
So the approximate area of the shaded region is 21.5cm^2
Answer:
12
Step-by-step explanation:
for this you need to draw a straight line and plot the points J,K,L,M,N according to the question.
here,
given K lies between J and M, L is between K and M , M is between K and N.
JN= 30, KM=8
JK=KL=LM
MJ= ?
according to the question,
J--------K-------L--------M-------N
KM= 8
KL+LM= 8 (KL+LM=KM)
KL+KL=8 ( given, LM=KL)
2KL= 8
KL=4
so,
JK= KL=4 and LM= KL= 4
now,
MJ= ?
we know
MJ= JK+KM = 4+8= 12
