The graph of a proportional relationship passes through (6, 48) and (1, y). Find y.

A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?

Travka [436]

Answer:

$area=\frac{85}{4}feet^{2}$

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

$perimeter=18\frac{1}{2}\\\\length=5$

$2(length+width)=perimeter$

Substitute,

$2(5+width)=18\frac{1}{2}$

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

$2(5+width)=\frac{37}{2}$

Inverse operations,

$2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}$

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

$length=5\\\\width = \frac{17}{4}$

$length*width=area$

Substitute,

$5*\frac{17}{4}\\\\=\frac{85}{4}$

$area=\frac{85}{4}feet^{2}$

4 0

3 years ago

The school that Emily goes to is selling tickets to the annual dance competition.

Vilka [71]

Answer:

price for senior citizen is $11

price for child ticket is $8

4 0

3 years ago

The mathematics department of a college has 6 male professors, 9 female professors, 5 male teaching assistants, and 6 female tea

Hitman42 [59]

Given:

6 male professores

9 female professores

5 male teaching assistants

6 female teaching assistants

Sol:.

$N(A\text{ or B)=N(A)+N(B)-N(A and B)}$

N (professors)

$\begin{gathered} =6+9 \\ =15 \end{gathered}$

N(Male)

$\begin{gathered} =6+5 \\ =11 \end{gathered}$

N(professors and male)

$=6$

N(professors OR male) = N(professors) + N(males) -N(professor OR male)

$\begin{gathered} N(\text{ Professors OR male)=15+11-6} \\ =20 \end{gathered}$

N(People to choose from)

$\begin{gathered} =6+9+5+6 \\ =26 \end{gathered}$

Then probablitiy is:

$\begin{gathered} =\frac{20}{26} \\ =\frac{10}{13} \end{gathered}$

Then the probability is 10/13

6 0

1 year ago

Seven subtracted from the quotient of a number and 2 is -6

Pachacha [2.7K]

N/2 -7 = -6

add 7 to both sides;
n/2 -7+7 = -6+7

n/2 = 1
multiply both sides by 2 ( or divide by 1/2 ) in order to get n by itself.

n/2 * 2/1 = 1 * 2/1

n = 2

5 0

3 years ago

Read 2 more answers

SOME ONE HELP!!!!! this test is due soon

valentina_108 [34]

Answer:

4.66 (4 2/3, 14/3)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers