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3 years ago

What arethe coordinates of the following point

Mathematics

1 answer:

yarga [219]3 years ago

7 0

Answer:

(a) Lying on both axes-

Point lying on both axes will lie on origin, so its coordinate is (0,0)

(b) Lying on x-axis and with x-coordinates 4

Since the point lies on x-axis so its y-coordinate is 0, so its coordinate is (4,0)

(c) Lying on y-axis and y-coordinates -3

Since the point lies on y-axis so its x-coordinate is 0, so its coordinate is (0,-3)

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3 years ago

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Solve for x.<br> Sqrt8 (Sqrt2 - x) = 11

Alexus [3.1K]

Answer: $\frac{-7\sqrt{2} }{4}$

Step-by-step explanation:

So first, let's get rid of the parentheses. We can multiply it out to get $\sqrt{16}-x\sqrt{8} =11$ . We know that the square root of 16 is ±4, so now our equation is ±4 - $x\sqrt{8}$ =11. I'm guessing since the problem only has one solution it's most likely only positive 4, so let's revise our equation to 4 - $x\sqrt{8}$ =11. We can use inverse operations to make the a little easier to solve: -7= $x\sqrt{8}$ . We divide both sides by $\sqrt{8}$ to get $\frac{-7}{\sqrt{8} } =x$ , which we can rationalize (remove the square root from the denominator so that it's a proper answer) by multiplying by $\frac{\sqrt{8} }{\sqrt{8} }$ (which is equal to one so we can use it) which is equal to $\frac{-7\sqrt{8} }{8}$ . Let's finish this by simplifying it. $\sqrt{8} =2\sqrt{2}$ (2x $2^{2}$ ). We can simplify it further by simplifying the 2, making it $\frac{-7\sqrt{2} }{4}$ .

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3 years ago

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Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartF

VladimirAG [237]

Answer:

Step 3

Step-by-step explanation:

The solution is given in the image attached. The steps are:

Step 1:

$2x-\frac{1}{4} -\frac{3}{5}x=\frac{55}{4}$

Step 2: simplifying the coefficients of x:

$2x -\frac{3}{5}x-\frac{1}{4}=\frac{55}{4}\\\frac{10x-3}{5} -\frac{1}{4}=\frac{55}{4}\\\frac{7x}{5} -\frac{1}{4}=\frac{55}{4}$

Step 3: Adding 1/4 to both sides

$\frac{7x}{5} -\frac{1}{4}+\frac{1}{4} =\frac{55}{4}+\frac{1}{4}\\ \frac{7x}{5}=\frac{55+1}{4}\\ \frac{7x}{5}=\frac{56}{4}\\$

Step 4: Multiplying both sides by 5/7

$\frac{7x}{5}*\frac{5}{7} =\frac{56}{4}*\frac{5}{7} \\x=10$

The addition property of equality states that if a number is added to both sides of an equation, the equation is still valid (i.e the equation is still the same). From the steps above, The addition property of equality was applied in step 3