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jek_recluse [69]
3 years ago
15

What arethe coordinates of the following point ​

Mathematics
1 answer:
yarga [219]3 years ago
7 0

Answer:

(a) Lying on both axes-  

Point lying on both axes will lie on origin, so its coordinate is (0,0)

(b) Lying on x-axis and with x-coordinates 4

Since the point lies on x-axis so its y-coordinate is 0, so its coordinate is (4,0)

(c) Lying on y-axis and y-coordinates -3

Since the point lies on y-axis so its x-coordinate is 0, so its coordinate is (0,-3)

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How many days are in 56 years and show work take a pic or on type
gavmur [86]
56*365=20440
56/4=14 (this is how many leap years are within 56 years)
20440+14=20454 days
6 0
3 years ago
Read 2 more answers
Find the length of line segment x.<br> A)<br> 4<br> B)<br> 5<br> 6<br> 7
Korolek [52]

Answer:

x = 6

Step-by-step explanation:

4(x + 4) = 5(3 + 5) => Intersecting Secants Theorem

4(x + 4) = 5(8)

Open the bracket

4x + 16 = 40

Subtract 16 from each side

4x + 16 - 16 = 40 - 16

4x = 24

4x/4 = 24/4

x = 6

4 0
3 years ago
Find the length of the following​ two-dimensional curve. r (t ) = (1/2 t^2, 1/3(2t+1)^3/2) for 0 &lt; t &lt; 16
andrezito [222]

Answer:

r = 144 units

Step-by-step explanation:

The given curve corresponds to a parametric function in which the Cartesian coordinates are written in terms of a parameter "t". In that sense, any change in x can also change in y owing to this direct relationship with "t". To find the length of the curve is useful the following expression;

r(t)=\int\limits^a_b ({r`)^2 \, dt =\int\limits^b_a \sqrt{((\frac{dx}{dt} )^2 +\frac{dy}{dt} )^2)}     dt

In agreement with the given data from the exercise, the length of the curve is found in between two points, namely 0 < t < 16. In that case a=0 and b=16. The concept of the integral involves the sum of different areas at between the interval points, although this technique is powerful, it would be more convenient to use the integral notation written above.

Substituting the terms of the equation and the derivative of r´, as follows,

r(t)= \int\limits^b_a \sqrt{((\frac{d((1/2)t^2)}{dt} )^2 +\frac{d((1/3)(2t+1)^{3/2})}{dt} )^2)}     dt

Doing the operations inside of the brackets the derivatives are:

1 ) (\frac{d((1/2)t^2)}{dt} )^2= t^2

2) \frac{(d(1/3)(2t+1)^{3/2})}{dt} )^2=2t+1

Entering these values of the integral is

r(t)= \int\limits^{16}_{0}  \sqrt{t^2 +2t+1}     dt

It is possible to factorize the quadratic function and the integral can reduced as,

r(t)= \int\limits^{16}_{0} (t+1)  dt= \frac{t^2}{2} + t

Thus, evaluate from 0 to 16

\frac{16^2}{2} + 16

The value is r= 144 units

5 0
3 years ago
Help me please, it would be great
Nastasia [14]
AB²=5²+5²+5²=25+25+25=75
AB=5√3≈8.7
Answer:AB≈8.7
4 0
3 years ago
Mr. Deveney bought 4 DVDs for $25.20. What was the price per DVD?
ollegr [7]

Answer:

$6.30 per DVD

Step-by-step explanation:

25.20/4= 6.3

7 0
3 years ago
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