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tekilochka [14]
3 years ago
8

what is the algebraic expression represents the phrase “the quotient of negative eight and the sum of a number and three”?

Mathematics
1 answer:
Advocard [28]3 years ago
5 0
You set it up like this.

So quotient means that you're dividing, so put a ÷
Next, it says the dividend, or the part being divided is -8, so now you have this: -8 ÷
Lastly, it says the divisor, or the part doing the dividing, is a quantity equal to the sum of "some number" (we'll use x) and 3. Since the divisor is one quantity collectively, you have to put it in parentheses.
This gives you: (x + 3)
When you put it all together, you get -8 ÷ (x + 3).
This can also be written as a fraction by putting -8 over (x+3).

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Which of the following demonstrates the Distributive Property?
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Answer this maths watch question step-by-step
Scilla [17]

The value of <u>a</u> is 2 and the value of <u>b</u> is 6.

<h3>Factoring</h3>

In math, factoring or factorization is used to write an algebraic expression in factors. There are some rules for factorization.  One of them is a factor out a common term for example: x²-x= x(x-1), where x is a common term.

You should factor the given expression.

2-\frac{x+3}{x+1}-\frac{x-5}{x-1}\\ \\ 2+\frac{-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \mathrm{Apply\:the\:fraction\:rule}:\quad \:a+\frac{b}{c}=\frac{ac+b}{c}\\ \\ \frac{2\left(x+1\right)\left(x-1\right)-\left(x+3\right)\left(x-1\right)-\left(x-5\right)\left(x+1\right)}{\left(x+1\right)\left(x-1\right)}\\ \\ \frac{2x+6}{\left(x+1\right)\left(x-1\right)}=\frac{2x+6}{x^2-1}

Read more about the factoring here:

brainly.com/question/11579257

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4 0
2 years ago
Two different numbers are selected simultaneously and at random from the set {1,2,3,4,5,6,7,8,9,10}. What is the probability tha
ehidna [41]

The probability of getting positive difference between the numbers 3 or greater between 1,2,3,4,5,6,7,8,9,10 if two numbers are selected is 28/45.

Given Numbers:{ 1,2,3,4,5,6,7,8,9,10}

We have to find the probability that the positive difference between the numbers selected is 3 or greater.

Probability is the likelihood of happening an event among all the events possible.

Total number of combinations when two numbers are selected from 10 numbers is 10 C 2=10!/2!(10-2)!

=10*9*8!/2*1(8!)

=10*9/2

=45 combinations

Combinations of numbers whose difference will be 3 or more are: (10,7),(10,6),(10,5),(10,4)(10,3)(10,2)(10,1)(9,6)(9,5)(9,4)(9,3)(9,2)(9,1)(8,5)(8,4)(8,3)(8,2)(8,1)(7,4)(7,3)(7,2)(7,1)(6,3)(6,2)(6,1)(5,2)(5,1)(4,1)

Total numbers =28

Probability=numbers/total combinations

=28/45

Hence the probability that two numbers selected gives difference of 3 or more is 28/45.

Learn more about probability at brainly.com/question/24756209

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6 0
2 years ago
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