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sammy [17]
3 years ago
10

PLZ ANSWER ASAP! I WILL REWARD BRAINLIEST AND 12 POINTS FOR THESE THREE QUESTIONS!

Mathematics
1 answer:
bezimeni [28]3 years ago
5 0

Answer:

1. 60%

2. $500

Explained:

10% = 50 in this case since  50 multiplied by 9 is 450

50 multiplied by 10 is 500

Which concludes that $500 was the original price and it was discounted by $50!

3. 16.4%

Explained:

I'll be saying the price is $100 for an example

If 12% is taken off the price, you still have to pay 88%

So, 88% in decimal form is 0.88. 100 multiplied by 0.88 equals 88.

Now we have to take off the 5%

So, after 5% you'll still have to pay 95%, and 88 multiplied by 0.95 equals 83.6

Now, if you subtract the 100 minus 83.6, it equals 16.4

Which means your answer is 16.4%

Hope I helped!

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Y=2x+4<br> y=x=6<br> i need help solving the system of equations
Temka [501]

Answer:

X = 6

Y = 6

Step-by-step explanation:

y = x = 6

we won’t pay attention to the first equation because this equation says that:   “y = x” and “x = 6”

so, if x = 6, so will be y

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3 years ago
MATH HELP PLEASE DRAW,, GEOMETRY ;3
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E(1,-4)  F(1,-6)  G(-3,-5)  H(-3,-3)

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Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
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3a+2b

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3(2) + 2(3)

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