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3 years ago

Please help me with this question. pls pls pls

Mathematics

1 answer:

vaieri [72.5K]3 years ago

4 0

Answer:

a) 11,10,9,8...1

b) 3,1,-1,-3...-15

Step-by-step explanation:

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Malachi has sticks that represent 4 different segment lengths: 3 inches, 4 inches, 5 inches, and 6 inches.

Dahasolnce [82]

Answer:

Create a triangle with the 3-, 4-, and 5-inch sticks and measure the angles to show that one angle is a right angle.

Step-by-step explanation:

6 0

2 years ago

Please help me, please please help ASAP!!!

shtirl [24]

Basically u evaluate it into (3⁶y⁵)² then use the properties of exponents to simplify to (729y⁵)² and then ur answer is 729²y¹⁰ or in other words, 3¹²•y¹⁰ so ur answer is B.

6 0

3 years ago

Which is higher 214.7 or 214.275

Lostsunrise [7]

easy 214.7 because if it was rounded it would be 214.700 an this is way bigger than 214.275

8 0

3 years ago

3. The curve C with equation y=f(x) is such that, dy/dx = 3x^2 + 4x +k

Andreas93 [3]

a. Given that y = f(x) and f(0) = -2, by the fundamental theorem of calculus we have

$\displaystyle \frac{dy}{dx} = 3x^2 + 4x + k \implies y = f(0) + \int_0^x (3t^2+4t+k) \, dt$

Evaluate the integral to solve for y :

$\displaystyle y = -2 + \int_0^x (3t^2+4t+k) \, dt$

$\displaystyle y = -2 + (t^3+2t^2+kt)\bigg|_0^x$

$\displaystyle y = x^3+2x^2+kx - 2$

Use the other known value, f(2) = 18, to solve for k :

$18 = 2^3 + 2\times2^2+2k - 2 \implies \boxed{k = 2}$

Then the curve C has equation

$\boxed{y = x^3 + 2x^2 + 2x - 2}$

b. Any tangent to the curve C at a point (a, f(a)) has slope equal to the derivative of y at that point:

$\dfrac{dy}{dx}\bigg|_{x=a} = 3a^2 + 4a + 2$

The slope of the given tangent line $y=x-2$ is 1. Solve for a :

$3a^2 + 4a + 2 = 1 \implies 3a^2 + 4a + 1 = (3a+1)(a+1)=0 \implies a = -\dfrac13 \text{ or }a = -1$

so we know there exists a tangent to C with slope 1. When x = -1/3, we have y = f(-1/3) = -67/27; when x = -1, we have y = f(-1) = -3. This means the tangent line must meet C at either (-1/3, -67/27) or (-1, -3).

Decide which of these points is correct:

$x - 2 = x^3 + 2x^2 + 2x - 2 \implies x^3 + 2x^2 + x = x(x+1)^2=0 \implies x=0 \text{ or } x = -1$

So, the point of contact between the tangent line and C is (-1, -3).

7 0

2 years ago

in a 30°-60°-90° triangle, the ( blank) is the (blank) the length of the ( blank) while the longer leg is ( blank) times the len

levacccp [35]

Answer:

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4 0

3 years ago