Question

I NEED HELP PLEASE. LOOK AT PICTURE

Answer 1

Answer:

Part 1) $\frac{a^4}{4b^2}$

Part 2) $-\frac{v^9}{w^6}$

Step-by-step explanation:

we know that

When divide exponents (or powers) with the same base, subtract the exponents

Part 1) we have

$\frac{3a^{2}b^{-4}}{12a^{-2}b^{-2}}=(\frac{3}{12})(a^{2+2})(b^{-4+2} )=\frac{1}{4}a^{4}b^{-2}=\frac{a^4}{4b^2}$

Part 2) we have

$\frac{v^3w^{-3}}{-v^{-6} w^3} =-v^{3+6}w^{-3-3}=-v^9w^{-6}=-\frac{v^9}{w^6}$